33. A 5.00-kg block is set into motion up an inclined plane with an initial speed of 8.00 m/s (Fig. P8.33). The block comes to rest after traveling 3.00 m along the plane, which is inclined at an angle of 30.0° to the horizontal, For this motion deter- mine (a) the change in the block's kinetic energy, (b) the change in the potential energy of the block-Earth system, and (c) the friction force exerted on the block (assumed to be constant). (d) What is the coefficient of kinetic friction? v;= 8.00O m/s 3.00 m 30.0° KER O h= 3Sin Figure P8.33
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- answer both....A 2.0kg block starts with a speed of 10. m/s at the bottom of a plane inclined at 35° to the horizontal. The coefficient of sliding friction between the block and the plane is 0.30. use the work-energy theorem to determine how far the block slides along the plane before momentarily coming to rest. A 2-kg block travels from the top of a plane inclined 25° with the horizontal compressing a spring at the bottom of the incline with an initial speed of 0.65 m/s. Due to the motion of the block, the spring was compressed by 0.2 meters. The spring has a k of 100 N/m and the coefficient of friction between the block and the incline is 0.40. What is the initial kinetic energy of the block? O -0.8) O 041 O -0.4)
- A 7.44-kg particle is subject to a net force that varies with position as shown in the figure. The particle starts from rest at x = 0. Fx (N) 3 2 2 4 6 8 10 12 14 16 What is its speed at the following positions? (a) x = 5.00 m 154.32 X Can you determine the kinetic energy of the particle at x = 5.00 m from the given graph? m/s (b) x = 10.0 m 154.33 x (m) X You appear to have added your result from part (a) to a speed calculated from the work done between 5 and 10 m. This doesn't work; you must calculate the work done over the entire 10 m distance. m/s (c) x = 15.0 m 151.31 X The force is positive throughout the entire interval. Does it make sense that the speed would decrease m/sHumans can produce an output power as great as 20 W/kg during extreme exercise. Sloths are not so energetic. At its maximum speed, a 4.0 kg sloth can climb a height of 6.0 m in 2.0 min. What’s the specific power for this climb?Same set-up for the conservation of energy was performed. The 5-g marble covered a horizontal distance of 40 cm from the edge of the ramp (horizontal) from an elevation of 15 cm above the ground. At what height (in cm) relative to edge of the ramp was the marble released? Use g=9.8 m/s2. Round off your answer to two decimal places.
- A skier (m=61.00 kg) starts sliding down from the top of a ski jump with negligible friction and takes off horizontally. If h = 6.70 m and D = 9.30 m, A) find H. B) Find her total kinetic energy as she reaches the ground.An object is dropped from a height of 50 m with zero initial velocity. Assuming 5% of the energy is lost to drag, what's the speed of the object when it hits the ground? A 19.4m/s (B) 9.8m/s © 47.5m/s (D 30.5 m/sA box of 9kg is released from rest on a rough inclined plane and slides to the bottom. The plane is inclined at a 230 angle to the horizontal and it is 5.1 m high. The coefficient of kinetic friction between the box and the plane is 0.1. Use conservation of energy to determine the speed of the block as it reaches the bottom.
- (8c7p19) A cord is used to vertically lower an initially stationary block of mass M = 45 ką at a constant downward acceleration of q/7. When the block has fallen a distance d = 4.5 m, find the work done by the cord's force on the block. Submit Answer Tries 0/5 Find the work done by the weight of the block. Submit Answer Tries 0/5 Find the kinetic energy of the block. Submit Answer Tries 0/5 Find the speed of the block. Submit Answer Tries 0/54) An archer draws his compound bow and shoots an arrow. The 25 g arrow leaves the bow with a velocity of 95 m/s. The power stroke of the bow is 57 cm; that is, the bowstring exerts force on the arrow through a displacement of 57 cm. The peak draw weight of the bow is 312 N. (This is the maximum force that the archer has to exert on the bowstring.) a. How much kinetic energy does the arrow have after release? b. If shot straight up, how high will the arrow go?1. A 5.00-kg block is set into motion up an inclined plane with an initial speed of v; = 8.00 m/s. The block comes to rest after traveling 3.00 m along the plane, which is inclined at an angle of 30.0° to the horizontal. For this motion determine (a) the change in the block's kinetic energy, (b) the change in the potential energy of the block- Earth system, and (c) the friction force exerted on the block (assumed to be constant). (d) What is the coefficient of kinetic friction?