32. How many grams of Li;N can be formed from 1.75 moles of Li? Assume an excess of nitrogen.6 Li(s) + N;(g) → 2 Li;N(s)A) 18.3 g LizNB) 20.3 g Li;NC) 58.3 g Li;ND) 15.1 g Li;NE) 61.0 g LizN

According to the mole concept, in terms of mass, the amount of substance in moles is equal to the…

Answered: 32. How many grams of Li;N can be…

32. How many grams of Li;N can be formed from 1.75 moles of Li? Assume an excess of nitrogen. 6 Li(s) + N2(g) → 2 Li¿N(s) A) 18.3 g Li;N B) 20.3 g Li;N C) 58.3 g Li;N D) 15.1 g Li;N E) 61.0 g Li;N

Introductory Chemistry: A Foundation

9th Edition

ISBN:9781337399425

Author:Steven S. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Donald J. DeCoste

Chapter8: Chemical Composition

Section: Chapter Questions

Problem 102AP: certain transition metal ion (Mn+) forms a compound with oxygen (MxOy) . The molar mass of the...

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Stoichiometry

Stoichiometry is a chemical division that evaluates the quantitative content of the chemical process with the help of the reacting molecules or products taking part in the reaction. The term “stoicheion” in “Stoichiometry”, is an old Greek term for "element" whereas “metron” means "measure".

Question

32. How many grams of Li;N can be formed from 1.75 moles of Li? Assume an excess of nitrogen.
6 Li(s) + N;(g) → 2 Li;N(s)
A) 18.3 g LizN
B) 20.3 g Li;N
C) 58.3 g Li;N
D) 15.1 g Li;N
E) 61.0 g LizN

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