32. HCOO is the conjugate base of HCOOH, The Ka for HCOOH is 1.8 X 10“. What is the Kb for HCOO? A) 1.8 X 106 B) 5.6 X 1011 C) 3.74 D) 1.0 X 10-14 33. Which of the following equations would correspond to the bicarbonate ion, HCO3', behaving as a weak acid? A) HCO3 (aq) + H2O (1) = H3O* (aq) + CO32 (aq) B) HCO3 (aq) + H20 (I) = H2CO3 (aq) + CO3? (aq) C) HCO3 (aq) + H2O (I) = H2CO3 (aq) + OH (aq) %3D D) HCO3 (aq) = CO2 (g) + OH" (aq)

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Chapter16: Acids And Bases
Section: Chapter Questions
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32. HCOO" is the conjugate base of HCOOH, The Ka for HCOOH is 1.8 X 10“. What
is the Kb for HCOO?
A) 1.8 X 106
B) 5.6 X 1011
C) 3.74
D) 1.0 X 10-14
33. Which of the following equations would correspond to the bicarbonate ion,
HCO3', behaving as a weak acid?
A) HCO3 (aq) + H2O (1) = H3O* (aq) + CO32 (aq)
B) HCO3 (aq) + H20 (I) = H2CO3 (aq) + CO3? (aq)
C) HCO3 (aq) + H2O (I) = H2CO3 (aq) + OH" (aq)
%3D
D) HCO3 (aq) = CO2 (g) + OH° (aq)
Transcribed Image Text:32. HCOO" is the conjugate base of HCOOH, The Ka for HCOOH is 1.8 X 10“. What is the Kb for HCOO? A) 1.8 X 106 B) 5.6 X 1011 C) 3.74 D) 1.0 X 10-14 33. Which of the following equations would correspond to the bicarbonate ion, HCO3', behaving as a weak acid? A) HCO3 (aq) + H2O (1) = H3O* (aq) + CO32 (aq) B) HCO3 (aq) + H20 (I) = H2CO3 (aq) + CO3? (aq) C) HCO3 (aq) + H2O (I) = H2CO3 (aq) + OH" (aq) %3D D) HCO3 (aq) = CO2 (g) + OH° (aq)
32. HCOO" is the conjugate base of HCOOH, The Ka for HCOOH is 1.8 X 10“. What
is the Kb for HCOO?
A) 1.8 X 106
B) 5.6 X 1011
C) 3.74
D) 1.0 X 10-14
33. Which of the following equations would correspond to the bicarbonate ion,
HCO3', behaving as a weak acid?
A) HCO3 (aq) + H2O (1) = H3O* (aq) + CO32 (aq)
B) HCO3 (aq) + H20 (I) = H2CO3 (aq) + CO3? (aq)
C) HCO3 (aq) + H2O (I) = H2CO3 (aq) + OH" (aq)
%3D
D) HCO3 (aq) = CO2 (g) + OH° (aq)
Transcribed Image Text:32. HCOO" is the conjugate base of HCOOH, The Ka for HCOOH is 1.8 X 10“. What is the Kb for HCOO? A) 1.8 X 106 B) 5.6 X 1011 C) 3.74 D) 1.0 X 10-14 33. Which of the following equations would correspond to the bicarbonate ion, HCO3', behaving as a weak acid? A) HCO3 (aq) + H2O (1) = H3O* (aq) + CO32 (aq) B) HCO3 (aq) + H20 (I) = H2CO3 (aq) + CO3? (aq) C) HCO3 (aq) + H2O (I) = H2CO3 (aq) + OH" (aq) %3D D) HCO3 (aq) = CO2 (g) + OH° (aq)
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