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32. f(x) = x² - 6x² + 5, [-3,5] J Lada.

32. f(x) = x² - 6x² + 5, [-3,5] J Lada.

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
do question 52
to sholicos 49-60 Find the absolute maximum and absolute minimum values of f on the given interval. 49. f(x) = 12 + 4x - x², [0, 5] 50. f(x) = 5 + 54x2x³, [0, 4] 51. f(x) = 2x³ 3x² 12x + 1, [-2,3] 32. f(x) = x² - 6x² + 5, [-3,5] 1 Toine norw 20
Transcribed Image Text:to sholicos 49-60 Find the absolute maximum and absolute minimum values of f on the given interval. 49. f(x) = 12 + 4x - x², [0, 5] 50. f(x) = 5 + 54x2x³, [0, 4] 51. f(x) = 2x³ 3x² 12x + 1, [-2,3] 32. f(x) = x² - 6x² + 5, [-3,5] 1 Toine norw 20
Expert Solution
Step 1

The given function is;

f(x)=x3-6x2+5, [-3,5].

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