32, 22 ≤ y ≤ 32 therwise of Y given that X = x. or 22 ≤ y ≤ 32 given that Y = y. or 22 ≤ x ≤ 32 is found to be 22 psi, what is the probability that the left tire has a pressure of at least 25 psi? (It is known that K = 3 442,4 d your answer to three decimal places.) is found to be 22 psi, what is the expected pressure in the left tire, and what is the standard deviation of pressure in this ti al places.) X psi psi
32, 22 ≤ y ≤ 32 therwise of Y given that X = x. or 22 ≤ y ≤ 32 given that Y = y. or 22 ≤ x ≤ 32 is found to be 22 psi, what is the probability that the left tire has a pressure of at least 25 psi? (It is known that K = 3 442,4 d your answer to three decimal places.) is found to be 22 psi, what is the expected pressure in the left tire, and what is the standard deviation of pressure in this ti al places.) X psi psi
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
P5.4

Transcribed Image Text:Each front tire on a particular type of vehicle is supposed to be filled to a pressure of 26 psi. Suppose the actual air pressure in each tire is a random variable-X for the right tire and Y for the left tire, with
joint pdf
f(x, y) =
x) = {K(x² + x²)
22 ≤ x ≤ 32, 22 ≤ y ≤ 32
otherwise
(a) Determine the conditional pdf of Y given that X = x.
fy|x(y|x) =
for 22 ≤ y ≤ 32
X
Determine the conditional pdf of X given that Y = y.
fxy(xly) =
for 22 ≤ x ≤ 32
X
3
Round your answer to three decimal
(b) If the pressure in the right tire is found to be 22 psi, what is the probability that the left tire has a pressure of at least 25 psi? (It is known that K =
places.)
442,400
Compare this to P(Y ≥ 25). (Round your answer to three decimal places.)
P(Y ≥ 25) =
X
3
(c) If the pressure in the right tire is found to be 22 psi, what is the expected pressure in the left tire, and what is the standard deviation of pressure in this tire? (It is known that K =
Round your answers to two decimal places.)
442,400
expected pressure
X psi
standard deviation
2.87107
psi
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