3/192 A particle is launched with a horizontal velocity vo = 0.55 m/s from the 30° position shown and then slides without friction along the funnel-like surface. Determine the angle which its velocity vector makes with the horizontal as the particle passes level O-O. The value of r is 0.9 m. 0 = 52.9° m 30° NO 0.15r- PROBLEM 3/192 om

Elements Of Electromagnetics
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**Problem 3/192**

A particle is launched with a horizontal velocity \( v_0 = 0.55 \, \text{m/s} \) from the 30° position shown and then slides without friction along the funnel-like surface. Determine the angle \( \theta \) at which its velocity vector makes with the horizontal as the particle passes level O-O. The value of \( r \) is 0.9 m.

**Diagram Explanation:**

- The diagram on the left shows a cross-sectional view of a funnel-like structure with a particle of mass \( m \). The particle is initially positioned at a 30° angle above the horizontal axis.
- The funnel has a radius of \( 0.15r \) from its center to the edge.
- The particle slides down this surface without friction.

- To the right, there's a top-down view of the funnel with the particle depicted at the center with its initial velocity \( v_0 \).

**Solution:** \( \theta = 52.9^\circ \)
Transcribed Image Text:**Problem 3/192** A particle is launched with a horizontal velocity \( v_0 = 0.55 \, \text{m/s} \) from the 30° position shown and then slides without friction along the funnel-like surface. Determine the angle \( \theta \) at which its velocity vector makes with the horizontal as the particle passes level O-O. The value of \( r \) is 0.9 m. **Diagram Explanation:** - The diagram on the left shows a cross-sectional view of a funnel-like structure with a particle of mass \( m \). The particle is initially positioned at a 30° angle above the horizontal axis. - The funnel has a radius of \( 0.15r \) from its center to the edge. - The particle slides down this surface without friction. - To the right, there's a top-down view of the funnel with the particle depicted at the center with its initial velocity \( v_0 \). **Solution:** \( \theta = 52.9^\circ \)
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