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31. The reaction 2NO(g) + Cl₂(g) →→→ 2NOCI(g) was studied at -10°C. The following results were obtained where [NO]. (mol/L) 0.10 0.10 0.20 A[C1₂] At Rate= -- [Cl₂]o (mol/L) 0.10 0.20 0.20 Initial Rate (mol/L - min) 0.18 0.36 1.45 a. What is the rate law? oder 0.18= K (.10M)(. 10M) first b. What is the value of the rate constant? K=18 K = 18

31. The reaction 2NO(g) + Cl₂(g) →→→ 2NOCI(g) was studied at -10°C. The following results were obtained where [NO]. (mol/L) 0.10 0.10 0.20 A[C1₂] At Rate= -- [Cl₂]o (mol/L) 0.10 0.20 0.20 Initial Rate (mol/L - min) 0.18 0.36 1.45 a. What is the rate law? oder 0.18= K (.10M)(. 10M) first b. What is the value of the rate constant? K=18 K = 18

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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AP Chemistry Unit 5 Problem Set 5.2: Differential Rate Laws (Method of Initial Rates) Problems from Zumdahl Chemistry, 10th Ed, Cengage Learning ©2017 31. The reaction 2NO(g) + Cl₂(g) →→→ 2NOCI(g) was studied at -10°C. The following results were obtained where [NO] (mol/L) 0.10 0.10 0.20 Rate = The reaction [Cl₂]o (mol/L) 0.10 0.20 0.20 A[CI₂] At Name Mary Claire Duffy Initial Rate (mol/L - min) 0.18 0.36 1.45 firs oro 2. What is he rate law? 0.18= K (₁10M) (₁10M) K = 18 a. b. What is the value of the rate constant? K=18
Transcribed Image Text:AP Chemistry Unit 5 Problem Set 5.2: Differential Rate Laws (Method of Initial Rates) Problems from Zumdahl Chemistry, 10th Ed, Cengage Learning ©2017 31. The reaction 2NO(g) + Cl₂(g) →→→ 2NOCI(g) was studied at -10°C. The following results were obtained where [NO] (mol/L) 0.10 0.10 0.20 Rate = The reaction [Cl₂]o (mol/L) 0.10 0.20 0.20 A[CI₂] At Name Mary Claire Duffy Initial Rate (mol/L - min) 0.18 0.36 1.45 firs oro 2. What is he rate law? 0.18= K (₁10M) (₁10M) K = 18 a. b. What is the value of the rate constant? K=18
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