solve question 31 with complete explanation within 15-30 mins and get multiple upvotes 30. Assuming that electrons enter the following parallel plate with a horizontal velocity of 3.20 x 106 m/ s,how far will the electrons travel horizontally before they crash into the positive plate? [5.58 x 10² m]31. A proton is placed in an electric field between two parallel plates. If the plates are 6.0 cm apart andhave a potential difference between them of 7.5 x 101 v, how much work is done against the electricfield when the proton is moved 3.0 cm parallel to the plates? [0]32. In the previous question, how much work would be done against the electric field if theproton was moved 3.0 cm perpendicular to the plates? [6.0 x 10-18 J]16. A charge of -5.00 C is separated from another charge of -2.00 C by a distance of 1.20 m. Calculatea) The net electric field midway between the two charges [7.49 x 1010 N/C [toward the -5.00 Ccharge]]b) The position where the net electric field is zero. [0.735 m from the -5.00 C charge]

In the given problem, a proton is moving parallel to the plates i.e there is no potential…

Answered: 31. A proton is placed in an electric…

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31. A proton is placed in an electric field between two parallel plates. If the plates are 6.0 cm apart and have a potential difference between them of 7.5 x 10² v, how much work is done against the electric field when the proton is moved 3.0 cm parallel to the plates? [0]