300,000 80,000 A D В fa C 60,000 160,000
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
Related questions
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I need some help with a
When I did this, I got confused in finding the flow rates... my answer doesn't resemble the
Could I get some assistance to better understand how to set up this problem and find the flow rates?
Thank you.

Transcribed Image Text:300,000
80,000+
A=
A
f₂
j= h
D
't
£₂ f₂
1
O
-1
Wef (4)
0
1
11
00000
O
1
to
f₁ - f3 + f5
f₂ +F3 -fs
fu + f5
fy
fy
f5=0 →
4
O
-1
1
0
B
с
410000
fa
f5 = 160,000-£q
fy
= 160,000 - fr
60,000
400-7
160,000
-1
fy fy
47-00
+ 160,000 -fy = 160,000
220,000
80,000
160,000
C
300,000
60,000
160,000
80, που
f₁-f3
00000
0
I
0
->
(A) 300,000
(8)
(c) fy + fy = 160,000
441100
= 220,000
f₁ = 220,000+ f3
₁ = ₁ + f₂ +60,000
f₂ + f₂ = fs +80,080
fy = fq
fs= fs
C
220,000
80,000
160,000
O
f₁ + f₂ = 300,000
→ f₁-f₂fy - 60,000
f₂+ fy - fs = 80,000
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