Please show all steps 11 300.0 mL of a 0.435 M solution of Nal is diluted to700.0 mL. What is the new concentration of thesolution?

Given NaI solution, Concentration(M1)=0.435 MVolume (V1)=300 mL=300×10-3LConcentration (M2)=M2Volume…

Answered: 300.0 mL of a 0.435 M solution of Nal…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Please show all steps

300.0 mL of a 0.435 M solution of Nal is diluted to
700.0 mL. What is the new concentration of the
solution?

Expert Solution

Step 1

Given NaI solution,

$C o n c e n t r a t i o n (M_{1}) = 0.435 M V o l u m e (V_{1}) = 300 m L = 300 \times 10^{- 3} L C o n c e n t r a t i o n (M_{2}) = M_{2} V o l u m e (V_{2}) = 700 m L = 700 \times 10^{- 3} m L$

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