30. What is the electrostatic force between two +1.0 C charges that are 0.5 m apart? (Coulomb's constant is 9.0 x 109 Nm2/c2; e -1.602 x 10 19 C) O 2.0 x 10° N O 3.6 x 10N O 1.8 x 1010 N O 4.0 x 10° N
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A: Solution:-Given thatq=7.51×10-6 Cd=4.54×10-6 mr=5.85 cm=0.0585 m
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- What is Fx on the charge at x = 16.00 cm if q = 2.650 C? Other charges are at 6000 cm and 2200 cm. Positive is correct. 8.988 109 Nm2/C2 is Coulomb constant. Fx || +0 3.506 Wrong +q 10.00-29 20.00+qx (cm)IP A particle with a mass of 4.0 g and a charge of +5.0x10-2 μC is released from rest at point A in the figure (Figure 1). Figure Ag 3.0 cm во 5.0 cm 4.0 cm OC E 1 of 1 L X > In which direction will this charge move? Positive Y- direction Negative y- direction Negative x-direction Positive x-direction Submit Part B V= Request Answer What speed will it have after moving through a distance of 5.5 cm ? The electric field has a magnitude of 1600 N/C Express your answer using two significant figures. 15. ΑΣΦ SFR P Pearson ? m/s104. In copper there is approximately one free electron for each atom. A copper coin has a mass of m=3 g. (k=9.10° N.m²/C², NA=6.02.10²3 mol-¹, e--1.6.10-¹9 C, M-63.5 g/mol) 1) What percentage of the free charge would have to be extracted from the currency for it to acquire a charge of q=15 UC? a)2,69.107 % b)2,99.107 % c)3,29.10.7 % d)3,59.10-7% e)3,89.107 % II) What would be the force of repulsion between two coins that have this charge, if they were separated by a distance of d = 25 cm? (Assume currency as a point charge) (a)30.4 N b)32.4 N (c)34.4 N (d)36.4 N (e)38.4 N
- 19. If a=3.0 mm, b=4.0 mm, Q₁ = 60 nC, Q₂ = 80 nC, and q=32 nC in the figure, what is the magnitude of the electric force on q? a. b. c. d. e. 1.6 N 1.3 N 1.9 N 2.2 N 0.040 N ID: A 20. Consider an electric dipole. The size of the dipole is small relatve to a point P located at a distance z from the dipole where the electric field is E. At a distance 3 times larger, the electric field is C. 9 times weaker d. 3 times stronger a. 27 times weaker b. 3 times weakerplease help with questions 28,29,303. Two small aluminium spheres weighing 10 g each are suspended by 10-cm-long silk threads from two hooks separated 10 cm apart. When the spheres are uncharged, the silk threads are vertical due to the gravitational pull of the earth (the effect of gravity between the two spheres is negligible). A fraction of the electrons from each sphere is then removed, leaving behind a net positive electric charge on each sphere. Once the spheres are charged, they move away from each other causing the thread to hang at 45 degrees from vertical. a) What is the net positive charge on each sphere? Hint: The horizontal and vertical forces acting on each sphere must be equal for the net force to be along a 45 degree angle. b) Given that the atomic mass of Aluminium is 27 and the atomic number is 13, what percentage of total electrons of the aluminium spheres need to be taken away to achieve this scenario?