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30 kip W = 2 kip/ft A В 10 ft. 20 ft. 30 ft. f. = 5000 psi 30 in. 36 in. 8 #9 bars 3 in. 3 in. 16 in. (a) Find the reactions at A and B. RA = kip, Rg = kip (b) Determine the maximum applied moment. Mmax =. ft*kip (c) Calculate the cracking moment of the beam and verify that the beam has cracked under the applied loads. Ma=. ft*kip

30 kip W = 2 kip/ft A В 10 ft. 20 ft. 30 ft. f. = 5000 psi 30 in. 36 in. 8 #9 bars 3 in. 3 in. 16 in. (a) Find the reactions at A and B. RA = kip, Rg = kip (b) Determine the maximum applied moment. Mmax =. ft*kip (c) Calculate the cracking moment of the beam and verify that the beam has cracked under the applied loads. Ma=. ft*kip

Structural Analysis
Structural Analysis
6th Edition
ISBN:9781337630931
Author:KASSIMALI, Aslam.
Publisher:KASSIMALI, Aslam.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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neutral axis of cracked section measured from top of beam, x =, in Ier = in (e) Compute the flexural stresses. Compressive stress of concrete at the top of the beam and tensile stresses at the centroid of the top and bottom layers of steel bars. Bending stress of concrete in extreme compression f. = psi Bending stress of top layer steel bars in tension f: = psi Bending stress of bottom layer steel bars in tension f: = psi
Transcribed Image Text:neutral axis of cracked section measured from top of beam, x =, in Ier = in (e) Compute the flexural stresses. Compressive stress of concrete at the top of the beam and tensile stresses at the centroid of the top and bottom layers of steel bars. Bending stress of concrete in extreme compression f. = psi Bending stress of top layer steel bars in tension f: = psi Bending stress of bottom layer steel bars in tension f: = psi
Transformed Area Method (Concrete Cracked - Elastic Stresses Stage) Problem 2) Modified Problem 2.13 (page 55, McCormac and Brown, 10th Ed.) Change f'c to 5 ksi and cross-sectional properties See figures below. 30 kip W = 2 kip/ft A 10 ft. 20 ft. 30 ft. f'. = 5000 psi 30 in. 36 in. 8 #9 bars 3 in. 3 in. 16 in. (a) Find the reactions at A and B. RA = kip, RB = kip ft*kip (b) Determine the maximum applied moment. Mmax = (c) Calculate the cracking moment of the beam and verify that the beam has cracked under the applied loads. Mer = ft*kip in3 Moment of inertia of gross section, Ig = Modulus of Rupture f, = (d) Calculate the cracked moment of inertia. Note that you will need to first calculate the concrete psi modulus of elasticity and modular ratio. Do not use the textbook modular ratio of n=8. Ec = psi (use the simplified equation for normal weight concrete) Modular ratio, n =
Transcribed Image Text:Transformed Area Method (Concrete Cracked - Elastic Stresses Stage) Problem 2) Modified Problem 2.13 (page 55, McCormac and Brown, 10th Ed.) Change f'c to 5 ksi and cross-sectional properties See figures below. 30 kip W = 2 kip/ft A 10 ft. 20 ft. 30 ft. f'. = 5000 psi 30 in. 36 in. 8 #9 bars 3 in. 3 in. 16 in. (a) Find the reactions at A and B. RA = kip, RB = kip ft*kip (b) Determine the maximum applied moment. Mmax = (c) Calculate the cracking moment of the beam and verify that the beam has cracked under the applied loads. Mer = ft*kip in3 Moment of inertia of gross section, Ig = Modulus of Rupture f, = (d) Calculate the cracked moment of inertia. Note that you will need to first calculate the concrete psi modulus of elasticity and modular ratio. Do not use the textbook modular ratio of n=8. Ec = psi (use the simplified equation for normal weight concrete) Modular ratio, n =
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