30 3 120 x f(x) = 2x-3 X + 1 n = 4 3 Pa(x) = 3 1+ x -x+x -3+ 5z- 522 +5-54 | Solution or Explanation 2x- 3 x + 1 2x + 2-5 X + 1 f(x) f(0) = -3 %3D %3D = 2- 5(x + 1)-1 f'(x) = 5(x + 1)-2 f"(x) = -10(x + 1)-3 30(x + 1)-4 R(X) =120(x + 1)-5 P4(x) =-3 + 5(x) f'(0) f"(0) f"'(0) A4)(0) 5. !! -10 = 30 f"(x) %3D = -120 10 24 = -3 + 5x - 5x2 + 5x3 - 5x4
30 3 120 x f(x) = 2x-3 X + 1 n = 4 3 Pa(x) = 3 1+ x -x+x -3+ 5z- 522 +5-54 | Solution or Explanation 2x- 3 x + 1 2x + 2-5 X + 1 f(x) f(0) = -3 %3D %3D = 2- 5(x + 1)-1 f'(x) = 5(x + 1)-2 f"(x) = -10(x + 1)-3 30(x + 1)-4 R(X) =120(x + 1)-5 P4(x) =-3 + 5(x) f'(0) f"(0) f"'(0) A4)(0) 5. !! -10 = 30 f"(x) %3D = -120 10 24 = -3 + 5x - 5x2 + 5x3 - 5x4
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Question
Can you please explain how did it get the 2x+2-5/x+1 on the first part? Where did -5 come from? Please explain the solution thank you
Transcribed Image Text:Practice Another
(x) =
2x-3
X +1
n = 4
PA(X) =3 1++x-x* +x
-3+ 5x-522 +5-54
|
Solution or Explanation
2x-3
X + 1
2x +2-5
X + 1
f(x)
(0)
= -3
= 2- 5(x + 1)-1
f'(x) = 5(x + 1)-2
f"(x) = -10(x + 1)-3
f"(X) = 30(x + 1)-4
0) = -120(x + 1)-5
Pa(x) --3 + 5(x) -
f (0)
f"(0)
f''(0)
A4)(0)
!!
= -10
= 30
= -120
10 ,2 + 30 x3
120
6.
24
= 3 + 5x - 5x2 + 5x3 - 5x4
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