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30 25. 2 k(k – 2)(k + 2). - k=1

30 25. 2 k(k – 2)(k + 2). - k=1

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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Numbers 25, 26,29
ao + ajx + a2x² + · · + anx" a5 + a4b + a³b² + a?b³ + ab4 + b5. (c) (d) In Exercises 18-25, use Theorem 5.4.2 to evaluate the sums. ww . r 100 100 2 k. E k. 18. k=1 k 3 100 20 20. Σ (7k + 1) . 21. Σ2 k= 1 k=1 20 6. 22. 23. (4k3 – 2k + 1). k=4 k = 1 30 2(k - k°). 25. 24. k(k - 2)(k + 2). k=1 k=1 In Exercises 26-30, express the sum in closed forrn. n-1 26. (a) (4k- 3) (b) k?. k=1 k= 1 n-1 2 n 3 k 27. 28. k=1 k=1 n-1 2k 30. ,2. n k=1 In Exercises 31-35, the limit of a function of n is given. hExpress the function of n in closed form, then find the limit. [Note: Although n assumes only integer values, the limits can be calculated using the same techniques that we have heen 1using for functions of a real-valued variable x.
Transcribed Image Text:ao + ajx + a2x² + · · + anx" a5 + a4b + a³b² + a?b³ + ab4 + b5. (c) (d) In Exercises 18-25, use Theorem 5.4.2 to evaluate the sums. ww . r 100 100 2 k. E k. 18. k=1 k 3 100 20 20. Σ (7k + 1) . 21. Σ2 k= 1 k=1 20 6. 22. 23. (4k3 – 2k + 1). k=4 k = 1 30 2(k - k°). 25. 24. k(k - 2)(k + 2). k=1 k=1 In Exercises 26-30, express the sum in closed forrn. n-1 26. (a) (4k- 3) (b) k?. k=1 k= 1 n-1 2 n 3 k 27. 28. k=1 k=1 n-1 2k 30. ,2. n k=1 In Exercises 31-35, the limit of a function of n is given. hExpress the function of n in closed form, then find the limit. [Note: Although n assumes only integer values, the limits can be calculated using the same techniques that we have heen 1using for functions of a real-valued variable x.
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