3.The number of flaws per square yard in a type of carpet material varies, with mean 1.6flaws per square yard and standard deviation 1.2 flaws per square yard. The distribution isnot normal--in fact, it is discrete. An inspector studies 200 random square yards of thematerial, records the number of flaws found in each square yard, and calculates the meannumber of flaws per square yard inspected. Use the central limit theorem to find theapproximate probability that the mean number of flaws exceeds 2 per square yard.4.Suppose the grades in a finite mathematics class are Normally distributed with a mean of75 and a standard deviation of 5. What is the probability that the average grade for 50randomly selected students was at least 83?

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Answered: 3.The number of flaws per square yard…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A CNC (computer numerical control) machine produces iron automobile crankshafts. Samples are measured and the inner diameter are found to be 1.01, 0.97, 1.03, 1.04, 0.99, 0.98, 0.99, 1.01, and 1.03 centimeters. For all computations, assume an approximately normal distribution. The sample mean and standard deviation for the given data are = 1.0056, and s =0.0246. Find a 99% confidence interval on the mean of diameter. Compute a 99% prediction interval on a measured diameter of a single crankshaft piece taken from the machine. Find the 99% tolerance limits that will contain most of the metal pieces produced by the CNC machine. O a. CI on the mean: 0.9781 <µ <1.0331. Prediction Interval: 0.9186 s Xp+151.0926. Tolerance Interval (0.8937 and 1.1175) O b. Insufficient data to compute. Missing the sample size n Oc CIon the mean: 0.9781 <µ<1.0331. Prediction Interval: 0.9186 s Xp+151.0926. Tolerance Interval (0.8937 and 1.1175). Insufficient data to compute for the Tolerance Interval Od. CI on…
let x be a ramdom variable with mean= 150 and standard deviation =4.2. Ramdom samples of fixed size n=30 are drawn from the distribution of x. determine the distribution, mean, and standard deviation of sample mean
Suppose a professor uses a normal distribution to assign grades in her math class. • She assigns an A to students scoring more than 1.9 standard deviations above the mean. • She assigns an F to students scoring more than 2.2 standard deviations below the mean. She assigns a B to students who Score between 1 and 1.9 standard deviations above the mean. • She assigns a D to students who Score between 1.2 and 2.2 standard deviations below the mean. • All other students get a C. Use the Cumulative Z-Score Table to answer the following questions. The Z-Score Table can be found below by selecting "Read". Write your answer as a percent using 2 decimal places. What percent of the class receives each grade assuming the scores are normally distributed? Hint % will recieve an A % will recieve a B % will recieve a C % will recieve a D % will recieve an F
The standard deviation of the distribution of sample means would be equal to:
Given a normal distribution with mean 100 and standard deviation 10, find the area under the normal curve from the mean to 112.9.
Suppose heights, in inches, of male orangutans have an unknown distribution with mean 60 and standard deviation 3 inches. A sample of size n = 49 is randomly taken from the population and the mean is taken. Using the Central Limit Theorem for Means, what is the sample mean distribution?
The height of an 8th grader is modeled using the normal distribution shown below. The mean of the distribution is 59.1 in and the standard deviation is 1.2 in. In the figure, Vis a number along the axis and is under the highest part of the curve. And, U and W are numbers along the axis that are each the same distance away from V. Use the empirical rule to choose the best value for the percentage of the area under the curve that is shaded, and find the values of U, V, and W. Percentage of total area shaded: (Choose one) V 56 58 60 62 Height (in inches)
A mean undergraduate cost for tuition , fees , room , and board for four-year institutions was 26,489 for a recent academic year. Suppose that the population standard deviation equals 3, 204 and 36 four year institutions are randomly selected .find the probability that the sample mean cost for these 36 schools is between 24,000 and 26, 000.find the corresponding area for the z values.
The annual rainfall in a certain region is modeled using the normal distribution shown below. The mean of the distribution is 36.5 cm and the standard deviation is 5.2 cm. In the figure, V is a number along the axis and is under the highest part of the curve. And, U and W are numbers along the axis that are each the same distance away from V. Use the empirical rule to choose the best value for the percentage of the area under the curve that is shaded, and find the values of U, V, and W. Percentage of total area shaded: (Choose one) ▼ 200 35 | 55 25 30 40 45 50 ( cm) Submit Continue |Privacy Center © 2022 McGraw Hill LLC. All Rights Reserved. Terms of Use DIl S0 FB F7 esc F3
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Suppose the distribution of heights of a group of 300 children is normal, with a mean of 150 centimeters and a standard deviation of 12 centimeters. About how many of these children are taller than 162 centimeters? children
Suppose NCSU students’ heights are normally distributed, with a mean height of 70in (5’10”) and a standard deviation of 4in.1. Calculate the Z score that can be used to assess the proportion of NCSU students shorter than 68 in.2. Calculate the Z score that can be used to assess the probability of obtaining a random sample of 100 NCSU students with average height less than 68 in.3. The standard normal distribution table is needed to tell exactly the proportion of NCSU students shorter than 68in and the probability of obtaining a random sample of 100 NCSU students with average height less than 68in. Can you tell whether they are the same?4. I draw a random sample of 121 NCSU freshmen. The sample’s average height is 71in, and standard deviation is 4in. Construct a 95% confidence interval and explain what the confidence interval tell you about the average height of NCSU freshmen.5. I draw a random sample of 121 NCSU freshmen. The sample’s average height is 71in, and standard deviation is…

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