3.Ifisgluen Wo Li 12 EI, A as Eg= EII EIz Find au expression. A for Ve at the enlof. the the overhomg beam Be using Tables in Appendin d
3.Ifisgluen Wo Li 12 EI, A as Eg= EII EIz Find au expression. A for Ve at the enlof. the the overhomg beam Be using Tables in Appendin d
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
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Question

Transcribed Image Text:3.IfOis glven
Wo Li
12 EI,
A
as Eg=
EII
EIz
expression TA
for Ve at the enelof.
Find au
--the
the overhomg beam Be using Tables in
Appendix gd

Transcribed Image Text:APPENDIX
CANTILEVERED BEAM SLOPES AND DEFLECTIONS
815
SLOPES AND
Cantilevered Beam Slopes and Deflections
DEFLECTIONS O
F
Beam
Slope
Deflection
Elastic Curve
BEAMS
"max
-PL
-PL'
Oman
(3L - x)
6EI
2EI
3EI
Simply Supported Beam Slopes and Deflections
Beam
Slope
Deflection
Elastic Curve
-P
12EL 3L - 2x) 0sxS L/2
P
-Px
(31 - 4x)
48EI
-5PL
-PL.
-PL.
-PL?
e =
SEI
16EI
48EI
48EI
4RET (6x - L) L/2 sxSI,
48EI
-Pab(L + b)
- Pbx
6EIL L - -
GEIL.
-a 12 - -
l' - - a')
6EIL
Pab(L + a)
-wl.'
(x2 - 41x + 62)
24EI
6EIL.
SEJ
-ML
-M, L
6EI
"max =
-Mox
9V3 EI
(L? - x)
6EIL
8, =
3EI
at x = 0.5774L
Mol
-wL
-5wL
-WX
r' - 2Lx + L')
M Vnas
El
2EI
Bmas
Pmax
24EI
24EI
384EI
-WN
(16r - 24Lx + 9L')
-SwL
384EI
- 3wl
768EI
0, =
0SxS L/2
24EI - 2Lx + L)
128EI
-wL
(8x
384EI
wL
2 =
24LX
7wL'
Fman - -0.006563
EI
-7wl"
2
8, =
+ 17Lx - L')
48EI
Emas
384EI
384EI
at x = 0.4598L
L/2 sx<I.
384EI (8t - LI
L/2 s xSL
-7w
"men = -0.00652
El
360EI
(3x - 10L' + 7L
360EIL
at x= 0.5193/.
6, =
45EI
-,L'
120EU (10L - 102x + 5Lx? - xP)
120EIL
814
24EI
30EI
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