3.An insurance company employs agents on a commission basis. It claims that in their first year, agents will earn a mean of at least 40.000TL and that the population standard deviation is no more than 6.000TL. A random sample of 9 agents are found for commissions in the first year and has values as follows: 9. Xi = 333000 ve (Xi – x)² = 312000 i=1 i=1 Where xị are the values for each agent and the distribution is normal. a.Test at the 0.05 significance level the null hypothesis that the population mean is at least 40.000TL and interpret the result b.Test at 0.10 significance level the null hypothesis that the population standard deviation is at most 6.000TL and interpret the result.

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3.An insurance company employs agents on a commission basis. It claims
that in their first year, agents will earn a mean of at least 40.000TL and that
the population standard deviation is no more than 6.00OTL. A random
sample of 9 agents are found for commissions in the first year and has
values as follows:
9.
9.
X; = 333000 ve
(Xi – x)2 = 312000
i=1
i=1
Where x; are the values for each agent and the distribution is normal.
a.Test at the 0.05 significance level the null hypothesis that the population
mean is at least 40.000TL and interpret the result
b.Test at 0.10 significance level the null hypothesis that the population
standard deviation is at most 6.000TL and interpret the result.
Transcribed Image Text:3.An insurance company employs agents on a commission basis. It claims that in their first year, agents will earn a mean of at least 40.000TL and that the population standard deviation is no more than 6.00OTL. A random sample of 9 agents are found for commissions in the first year and has values as follows: 9. 9. X; = 333000 ve (Xi – x)2 = 312000 i=1 i=1 Where x; are the values for each agent and the distribution is normal. a.Test at the 0.05 significance level the null hypothesis that the population mean is at least 40.000TL and interpret the result b.Test at 0.10 significance level the null hypothesis that the population standard deviation is at most 6.000TL and interpret the result.
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