3.90. There are four numbered balls in a box: 2 white and 2 black. In how many ways can 2 balls be chosen, among which at most one will be black? (a) List all the possibilities. b) Why the number of ways in point a ) cannot be calculated in the following way: we choose one white ball in 1 ways and another ball any of the remaining balls in ways, 1 so together we have 2· 3=6ways?

A First Course in Probability (10th Edition)
10th Edition
ISBN:9780134753119
Author:Sheldon Ross
Publisher:Sheldon Ross
Chapter1: Combinatorial Analysis
Section: Chapter Questions
Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
icon
Related questions
Question
3.90. There are four numbered balls in a box: 2 white and 2 black. In how many ways can 2 balls be
chosen, among which at most one will be black?
(a) List all the possibilities.
b) Why the number of ways in point a) cannot be calculated in the following way: we choose one
2
ways and another ball any of the remaining balls in ways,
3
white ball in
so together we have
1
1
2·3=6ways?
Transcribed Image Text:3.90. There are four numbered balls in a box: 2 white and 2 black. In how many ways can 2 balls be chosen, among which at most one will be black? (a) List all the possibilities. b) Why the number of ways in point a) cannot be calculated in the following way: we choose one 2 ways and another ball any of the remaining balls in ways, 3 white ball in so together we have 1 1 2·3=6ways?
Expert Solution
steps

Step by step

Solved in 3 steps

Blurred answer
Similar questions
Recommended textbooks for you
A First Course in Probability (10th Edition)
A First Course in Probability (10th Edition)
Probability
ISBN:
9780134753119
Author:
Sheldon Ross
Publisher:
PEARSON
A First Course in Probability
A First Course in Probability
Probability
ISBN:
9780321794772
Author:
Sheldon Ross
Publisher:
PEARSON