3.75 m/s 4.75 L. m/s 27.5

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A 375 gram basketball is bounced off of a wooden board, as shown below. It is moving straight down at a speed of 4.75 m/s just before hitting the board, and it is moving with a speed of 3.75 m/s at an angle of 27.5 degrees above the horizontal just after. The ball is in contact with the board for a total of 68.5 milliseconds (ms).

A)Find the average force that the board exerts on the ball during the bounce. Give the magnitude of the force in units of Newtons. Give the direction of the force as an angle from the x-axis, in degrees. 

B) How much kinetic energy is lost as a result of the ball hitting the board? Give your answer in Joule

3.75
m/s
4.75
L.
m/s
27.5
Transcribed Image Text:3.75 m/s 4.75 L. m/s 27.5
Expert Solution
Step 1

Given values,

Mass of basketball, m=375 g=0.375 Kg

time of contact, t=68.5 ms=0.0685 s

Before collision:

velocity in y-direction, uy=4.75 m/s in negative y-direction

velocity in x-direction, ux=0

After collision:

velocity in x-direction, vx=3.75 cos27.50=3.33 m/s in positive x-direction

velocity in y-direction, vy=3.75 sin27.50=1.73 m/s in positive y-direction

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