3.7 Required: Given, : distance between the charger, r = ? magnitude of equal charges, 9₁ = 92 = 75×10 °c Force between charges, F = 1 N Formula used: F = ± 4760 21%2 342 [Coulomb's Law] Now F = 1 47760 9192 912 05, 2 = 4760 9192 F = 10 x 750 75×10 9 • [uh% = 2xv° _svw/e2] 1 0% 4² = 9x75x75 × 10 ×109 6 2² = 50.625×10 05 M = √50.625×10 - 7.12×10 m or, -3 Criven, Hence, M = 7.12×10 m the required distance is 7.12×103 m 4.7 Required: magnitude of force, F = ? magnitude of equal charges, a₁ = 92 = distance M= 1×103³ m Formula used, F = L URGO 9192 242 Now, F = 9x10 x 35×35 (1x103)2 0% F = 1.1×10 N Hence, the required force is 1. 1×10t N 35 C 9x109 x 35x35 1×106 = 1.1×10 N 7
3.7 Required: Given, : distance between the charger, r = ? magnitude of equal charges, 9₁ = 92 = 75×10 °c Force between charges, F = 1 N Formula used: F = ± 4760 21%2 342 [Coulomb's Law] Now F = 1 47760 9192 912 05, 2 = 4760 9192 F = 10 x 750 75×10 9 • [uh% = 2xv° _svw/e2] 1 0% 4² = 9x75x75 × 10 ×109 6 2² = 50.625×10 05 M = √50.625×10 - 7.12×10 m or, -3 Criven, Hence, M = 7.12×10 m the required distance is 7.12×103 m 4.7 Required: magnitude of force, F = ? magnitude of equal charges, a₁ = 92 = distance M= 1×103³ m Formula used, F = L URGO 9192 242 Now, F = 9x10 x 35×35 (1x103)2 0% F = 1.1×10 N Hence, the required force is 1. 1×10t N 35 C 9x109 x 35x35 1×106 = 1.1×10 N 7
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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