I need the answer as soon as possible 3.46 Derive the equation of motion and find the steady-state response of the system shown in Fig. 3.54for rotational motion about the hinge O for the following data: k = 5000 N/m,|-1 m, c - 1 000 N-s/m, m - 10 kg. Mo = 100 N-m, w = 1000 rpm.Housing withing(a)Runway(b)FIGU. 3.52 Modeling of lanPROBLEMS349Grindingwheelarindingmachine) = Y sin ot= Y sin 200 mt mFloorFICRE 3.53Uniformrigid bar,ITICmass mkMg cos ot*--FIGURE 3.54

For solution refer below images.

3.46 Derive the equation of motion and find the steady-state response of the system shown in Fig. 3.54 for rotational motion about the hinge O for the following data: k = 5000 N/m, 1-1 m, c - 1000 N-s/m, m - 10 kg, Mo = 100 N-m, w = 1000 rpm.

3.46 Derive the equation of motion and find the steady-state response of the system shown in Fig. 3.54 for rotational motion about the hinge O for the following data: k = 5000 N/m, 1-1 m, c - 1000 N-s/m, m - 10 kg, Mo = 100 N-m, w = 1000 rpm.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

How do we get 2.264 and .4415?
Texts: A haulage gear is driven by a motor which develops 15 kW at a full speed of 750 rev/min. The haulage drum is 1.5 m in diameter, and the total reduction ratio of the gearing between the motor and drum is 15:5. The efficiency of the gear is 75 percent, the gradient is 1 in 25, and the rail friction is 135 N per tonne of load. The masses of the gear are equivalent to a total mass of 2.3 Mg, with a radius of gyration of 0.5 m at the drum shaft. Calculate the total load that can be hauled at the full speed. If the motor can give an excess torque of 10 percent of that at full speed, calculate the acceleration possible, assuming that the efficiency and rail friction values remain unaltered.
Please solve for me handwriting request to u please solve all for me what i ask i requested to u solve all handwriting thanks ?.
Two shafts, 1.67 ft apart, are connected by an open belt. The input shaft has a speed of 350 rpm and the output shaft should be capable of running at speeds of 950 rpm, 650 rpm, 450 rpm, 250 rpm, and 150 rpm. If the diameter of the smallest pulley on the driven shaft is 2 inches, calculate the length of the belt and the diameters of each pulleys attached at the shafts.
Give the steps by steps explanation of the previous answer
Please answer ASAP! Please show the complete solutions. Rate will be given. No long explanation needed. Answer in 3 decimal places. Mechanics of Deformable Bodies A steel circular shaft (G= 80 GPa) of constant diameter of 28 mm is subjected to the following torques in N-m: TA= 160; TB = 130; TC = 350; TD = 380. The directions of the applied torques are indicated in the figure The bearings shown allow the shaft to turn freely. The length of each segment is equal to 86 cm. (a) Plot a torque diagram showing the internal torque in segments (1), (2) and (3) of the shaft. Show the FBD of each segment using a double-headed arrow to represent each torque. Use the same rule of signs as in the lecture. Determine (b) the maximum stress in the shaft in MPa (C) rotation angle of pulley B with respect to pulley D. Solid shaft: J= (pi/32 X D4) Hollow: J= (pi/32xD4-d4) Note: Please Follow rule of signs and show complete FBD of each section
why is the length of the wire use in finding the centripetal force instead of the radius?
Part c
A pair of forces acting directly on the material to reduce in its length are called Select one: Friction force Slipping force Compressive force Direct force
For step one, I got the same values but negative
I need the answer as soon as possible
Please derive this equation