3.4-8 Channel utilization with pipelining. Suppose a packet is 10K bits long, the channel transmission rate connecting a sender and receiver is 10 Mbps, and the round-trip propagation delay is 10 ms. What is the channel utilization of a pipelined protocol with an arbitrarily high level of pipelining for this channel? 3.4-8 Channel utilization with pipelining. Suppose a packet is 10K bits long, the channel transmission rate connecting a sender and receiver is 10Mbps, and the round-trip propagation delay is 10 ms. What is the channel utilization of a pipelined protocol with an arbitrarily high level of pipeliningfor this channel?0.0010.010.11.010.0

Correct answer - (C) 0.1Transmission time = L/B = 10K/10Mbps = 1ms Round trip time = 10ms Round trip time = 2*Propagation Delay Throughput = Transmission time /(transmission time+ 2*propagation time) = 1 /( 1 + 10) = 1/11 = 0.0909 = 0.1

Answered: 3.4-8 Channel utilization with…

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3.4-8 Channel utilization with pipelining. Suppose a packet is 10K bits long, the channel transmission rate connecting a sender and receiver is 10 Mbps, and the round-trip propagation delay is 10 ms. What is the channel utilization of a pipelined protocol with an arbitrarily high level of pipelining for this channel?

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