3.38. (a) As in Problem 3.37, I measure the velocities, v₁ and v₂, of a glider at two points on a sloping air track with the results given there. Instead of measuring the time between the two points, I measure the distance as d = 3.740 ± 0.002 m. If I now calculate the acceleration as a = (v₂² − v₁²)/2d, what should be my answer with its uncertainty? (b) How well does it agree with my theoretical prediction that a = 0.13 ± 0.01 m/s²? 0.85±0.05 m/s. For Note: for problem 3.38, use v₁ = = 0.21±0.05 m/s and v₂ part b), use a t-score to compare the two values.
3.38. (a) As in Problem 3.37, I measure the velocities, v₁ and v₂, of a glider at two points on a sloping air track with the results given there. Instead of measuring the time between the two points, I measure the distance as d = 3.740 ± 0.002 m. If I now calculate the acceleration as a = (v₂² − v₁²)/2d, what should be my answer with its uncertainty? (b) How well does it agree with my theoretical prediction that a = 0.13 ± 0.01 m/s²? 0.85±0.05 m/s. For Note: for problem 3.38, use v₁ = = 0.21±0.05 m/s and v₂ part b), use a t-score to compare the two values.
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Disregard the part about 3.37. Refer to the note at the bottom of the question for v1 and v2 values. Help on part B please
Transcribed Image Text:3.38. (a) As in Problem 3.37, I measure the velocities, v₁ and v₂, of a glider at
two points on a sloping air track with the results given there. Instead of measuring
the time between the two points, I measure the distance as
d = 3.740 ± 0.002 m.
If I now calculate the acceleration as a = (v₂² − v₁²)/2d, what should be my answer
with its uncertainty? (b) How well does it agree with my theoretical prediction that
a = 0.13 0.01 m/s²?
0.85±0.05 m/s. For
=
Note: for problem 3.38, use v₁ = 0.21±0.05 m/s and v₂
part b), use a t-score to compare the two values.
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