3.364 g of hydrated barium chloride BaCl2.xH2O was dissolved in water and made up to a total volume of 250.0 mL. 10.00 mL of this solution required 46.92 mL of 2.530 x 10² M silver nitrate for complete reaction. Calculate the value of x in the formula of hydrated barium chloride, given the net ionic equation for precipitation below. (4) Cl(aq) + Ag*(aq) → AgCl(s)

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3.364 g of hydrated barium chloride BaCl2.XH2O was dissolved in water and made up to a total volume of
250.0 mL. 10.00 mL of this solution required 46.92 mL of 2.530 x 102 M silver nitrate for complete
reaction. Calculate the value of x in the formula of hydrated barium chloride, given the net ionic equation
for precipitation below. (4)
Cl'(aq) + Ag*(aq) → AgCl(s)
Transcribed Image Text:3.364 g of hydrated barium chloride BaCl2.XH2O was dissolved in water and made up to a total volume of 250.0 mL. 10.00 mL of this solution required 46.92 mL of 2.530 x 102 M silver nitrate for complete reaction. Calculate the value of x in the formula of hydrated barium chloride, given the net ionic equation for precipitation below. (4) Cl'(aq) + Ag*(aq) → AgCl(s)
Expert Solution
Step 1

Mass of hydrated barium chloride (BaCl2.xH2O) = 3.364 g

Total volume of barium chloride (V) = 250 ml

Volume taken for titration V = 10 ml

Volume of AgNO3 consumed = 46.92 ml

Concentration of AgNO3 = 2.53 x 10-2 M

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