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3.32. How far below the water surface should a vertical square, 1.22 m on a side with two sides horizontal, be immersed so that the center of pressure will be 76 mm below the center of gravity? What will be the total force on the square? Ans. 1.01 m, 23.7 kN 3.33. In Fig. 3-26, the 4-ft-diameter cylinder, 4 ft long, is acted upon by water on the left and oil of sp gr 0.800 on the right. Determine (a) the normal force at B if the cylinder weighs 4000 lb and (b) the horizontal force due to oil and water if the oil level drops 1 ft. Ans. 1180 lb, 3100 lb to right B Fig. 3-26 Oil 3.34. For the inclined circular gate 1.0 m in diameter with water on one side, shown in Fig. 3-27, find the total resultant force acting on the gate and the location of the center of pressure. Ans. 14.86 kN, 2.260 m below water surface measured along inclination of gate

3.32. How far below the water surface should a vertical square, 1.22 m on a side with two sides horizontal, be immersed so that the center of pressure will be 76 mm below the center of gravity? What will be the total force on the square? Ans. 1.01 m, 23.7 kN 3.33. In Fig. 3-26, the 4-ft-diameter cylinder, 4 ft long, is acted upon by water on the left and oil of sp gr 0.800 on the right. Determine (a) the normal force at B if the cylinder weighs 4000 lb and (b) the horizontal force due to oil and water if the oil level drops 1 ft. Ans. 1180 lb, 3100 lb to right B Fig. 3-26 Oil 3.34. For the inclined circular gate 1.0 m in diameter with water on one side, shown in Fig. 3-27, find the total resultant force acting on the gate and the location of the center of pressure. Ans. 14.86 kN, 2.260 m below water surface measured along inclination of gate

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
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52 HYDROSTATIC FORCE ON SURFACES CES 3.29. In Fig. 3-25, the 4-ft-diameter semicylindrical gate is 3 ft long. If the coefficient of friction between the Ans. 347 lb. gate and its guides is 0.100, find the force F required to raise the 1000-lb gate. 3.30. 3.31. Fig. 3-25 [CHAP. 3 A tank with vertical sides contains 0.914 m of mercury and 5.029 m of water. Find the total force on a square portion of one side 0.61 m by 0.61 m in area, half of this area being below the surface of the mercury. The sides of the square are horizontal and vertical. Ans. 21.8 kN, 5.069 m down An isosceles triangle, base 18 ft and altitude 24 ft, is immersed vertically in oil of specific gravity 0.800 with its axis of symmetry horizontal. If the head on the horizontal axis is 13 ft, determine the total force on one face of the triangle and locate the center of pressure vertically. Ans. 140,400 lb: 14.04 ft 3.32. How far below the water surface should a vertical square, 1.22 m on a side with two sides horizontal, be immersed so that the center of pressure will be 76 mm below the center of gravity? What will be the total force on the square? Ans. 1.01 m, 23.7 kN 3.33. In Fig. 3-26, the 4-ft-diameter cylinder, 4 ft long, is acted upon by water on the left and oil of sp gr 0.800 on the right. Determine (a) the normal force at B if the cylinder weighs 4000 lb and (b) the horizontal force due to oil and water if the oil level drops 1 ft. Ans. 1180 lb, 3100 lb to right keep the B Fig. 3-26 Oil 3.34. For the inclined circular gate 1.0 m in diameter with water on one side, shown in Fig. 3-27, find the total resultant force acting on the gate and the location of the center of pressure. Ans. 14.86 kN, 2.260 m below water surface measured along inclination of gate 3.35. In Fig. 3-28, for a length of 8 ft determine the unbalanced moment about the hinge O due to water at level Ans. 18,000 ft-lb clockwise A.
Transcribed Image Text:52 HYDROSTATIC FORCE ON SURFACES CES 3.29. In Fig. 3-25, the 4-ft-diameter semicylindrical gate is 3 ft long. If the coefficient of friction between the Ans. 347 lb. gate and its guides is 0.100, find the force F required to raise the 1000-lb gate. 3.30. 3.31. Fig. 3-25 [CHAP. 3 A tank with vertical sides contains 0.914 m of mercury and 5.029 m of water. Find the total force on a square portion of one side 0.61 m by 0.61 m in area, half of this area being below the surface of the mercury. The sides of the square are horizontal and vertical. Ans. 21.8 kN, 5.069 m down An isosceles triangle, base 18 ft and altitude 24 ft, is immersed vertically in oil of specific gravity 0.800 with its axis of symmetry horizontal. If the head on the horizontal axis is 13 ft, determine the total force on one face of the triangle and locate the center of pressure vertically. Ans. 140,400 lb: 14.04 ft 3.32. How far below the water surface should a vertical square, 1.22 m on a side with two sides horizontal, be immersed so that the center of pressure will be 76 mm below the center of gravity? What will be the total force on the square? Ans. 1.01 m, 23.7 kN 3.33. In Fig. 3-26, the 4-ft-diameter cylinder, 4 ft long, is acted upon by water on the left and oil of sp gr 0.800 on the right. Determine (a) the normal force at B if the cylinder weighs 4000 lb and (b) the horizontal force due to oil and water if the oil level drops 1 ft. Ans. 1180 lb, 3100 lb to right keep the B Fig. 3-26 Oil 3.34. For the inclined circular gate 1.0 m in diameter with water on one side, shown in Fig. 3-27, find the total resultant force acting on the gate and the location of the center of pressure. Ans. 14.86 kN, 2.260 m below water surface measured along inclination of gate 3.35. In Fig. 3-28, for a length of 8 ft determine the unbalanced moment about the hinge O due to water at level Ans. 18,000 ft-lb clockwise A.
CHAP. 31 1.5 m sin 60° m 3.38. PER 14 kPa 0.91 m HYDROSTATIC FORCE ON SURFACES Water Fig. 3-29 hos 1.m 0061m RETI Fig. 3-27 Fig. 3-28 1.5 m sin 60° B 3.36. The tank whose cross section is shown in Fig. 3-29 is 1.2 m long and full of water under pressure. Find the components of the force required to keep the cylinder in position, neglecting the weight of the cylinder. Ans. 14 kN down, 20 kN to left Уся CG CP 3.37. Determine, per foot of length, the horizontal and vertical components of water pressure acting on the Tainter-type gate shown in Fig. 3-30. Ans. 3120 and 1130 lb 60° Yep D 10' Fig. 3-30 20' R 53 0 1 Find the vertical force acting on the semicylindrical dome shown in Fig. 3-31 when gage A reads 58.3 kPa. The dome is 1.83 m long. Ans. 113 kPa
Transcribed Image Text:CHAP. 31 1.5 m sin 60° m 3.38. PER 14 kPa 0.91 m HYDROSTATIC FORCE ON SURFACES Water Fig. 3-29 hos 1.m 0061m RETI Fig. 3-27 Fig. 3-28 1.5 m sin 60° B 3.36. The tank whose cross section is shown in Fig. 3-29 is 1.2 m long and full of water under pressure. Find the components of the force required to keep the cylinder in position, neglecting the weight of the cylinder. Ans. 14 kN down, 20 kN to left Уся CG CP 3.37. Determine, per foot of length, the horizontal and vertical components of water pressure acting on the Tainter-type gate shown in Fig. 3-30. Ans. 3120 and 1130 lb 60° Yep D 10' Fig. 3-30 20' R 53 0 1 Find the vertical force acting on the semicylindrical dome shown in Fig. 3-31 when gage A reads 58.3 kPa. The dome is 1.83 m long. Ans. 113 kPa
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