3.3 Verify that 98.8 A is the maximum conductor current that does not exceed the voltage drop limit of 5% in Example 3.2. Compute the current that results in a 10% drop.

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Example 3.2 The conductors of a 15 km long, 22 kV distribution line have a
cross-sectional area of 100 mm². The conductors have a resistivity of 0.274
S2/km and are spaced so that « = 1.2. The ampacity is 313 A. Compute the
power rating of the line, the voltage drop, and the losses when operating at the
rated ampacity.
Solution The power rating of the line is
22 kV
Srated, total = 3 x Irated × Vø = 3 × 313 ×
11.93 MVA.
V3
The impedance of each conductor is
Zline = Rjine +jX]ine = 0.274 × (1 +j«) × 15 = 4.110+j4.932 N.
When operating at the rated ampacity, the voltage drop is
Vdrop = Irated × |Zlinel = 313 × |4.110 + j4.932| = 2.009 kV
and the power loss for the line, accounting for all phases:
Ploss, total = 3 x Inted × Rrated = 3 × 313² × 4.101 = 1.208 MW.
%3D
Transcribed Image Text:Example 3.2 The conductors of a 15 km long, 22 kV distribution line have a cross-sectional area of 100 mm². The conductors have a resistivity of 0.274 S2/km and are spaced so that « = 1.2. The ampacity is 313 A. Compute the power rating of the line, the voltage drop, and the losses when operating at the rated ampacity. Solution The power rating of the line is 22 kV Srated, total = 3 x Irated × Vø = 3 × 313 × 11.93 MVA. V3 The impedance of each conductor is Zline = Rjine +jX]ine = 0.274 × (1 +j«) × 15 = 4.110+j4.932 N. When operating at the rated ampacity, the voltage drop is Vdrop = Irated × |Zlinel = 313 × |4.110 + j4.932| = 2.009 kV and the power loss for the line, accounting for all phases: Ploss, total = 3 x Inted × Rrated = 3 × 313² × 4.101 = 1.208 MW. %3D
3.3 Verify that 98.8 A is the maximum conductor current that does not exceed the
voltage drop limit of 5% in Example 3.2. Compute the current that results in a 10%
drop.
Transcribed Image Text:3.3 Verify that 98.8 A is the maximum conductor current that does not exceed the voltage drop limit of 5% in Example 3.2. Compute the current that results in a 10% drop.
Expert Solution
Step 1

As we have given:

Irated=98.8 A% Vdrop=10%

 

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