3.2 Replace the force system acting on the beam by an equivalent force-couplesystem with the force acting at (a) point A; and (b) point B.36 kNУ94 kN mхB2 m2 m3 m16 kN20 kNFigure P3.2

First, understand the concept of how a force is replaced from one point to another point. If a force…

Answered: 3.2 Replace the force system acting on…

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

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Example 3- Home work Determine the couple moment acting on the pipe. Segment AB is directed 30°below the x-y plane. 250 N 0.8 m 300 250 N 0.6 m B
Problem 4.39 Consider the system shown in (Figure 1). Figure 70 F-80 lb 8 CISA 16 15 58 1 of 1 Part A Determine the moment of the force F about the door hinge at B. Express the result as components of a Cartesian vector. Enter the x, y, and components of the moment in pound-feet to three significant figures and separated by commas. (Ms),.(Ms), (Ms) = Submit Provide Feedback Request Answer 195| ΑΣΦ. 241 | vec A A C ? lb-ft
(Q 3.77) If P=2016 in the figure, replace the three couples with a single equivalent couple, specifying its magnitude and the direction of its axis. 10 in. A A: F₁ 16 lb 40 lb 15 in.. E 40 lb F₂1161b 10 in. 10 in. P Fu.
If you know that the moment of the force F about point A should look like the formula: M, i+ M,j• M, k, what is the value of the M,? knowing that the force vector equals to: F= -160.11 + -624.2) + 867Ak lb Note: Your answer should contain only numbers, not units. F B 8 ft 1.5 ft 0.25 ft
(a) Determine the magnitudes and coordinate direction angles of F3 so that the resultant force of the three forces is zero. Refer figure Ql(a) below. Q1. F, F1 = 400N 40 30 F2 = 600N Figure Q1(a) Q1 the moment(MB) of this force about point B. (b) Figure Q1 (b) shows the pipe assembly is subjected to the 100N force. Determine 400 mm 300 mm 200 mm 200 mm 250 mm 40° 30 F = 100N Figure Q1(b)
For the pipe frame pictured below: Replace all forces and the couple by the equivalent resultant force R acting on point O and a couple Mo (written as vectors) Describe this system as the wrench, resultant force R and wrench moment M (written as vectors) Specify the coordinates of the point, P in the x-y plane, through which the line of action of the wrench passes (x,y) (Hint: Watch your units for each term and directions as you calculate moments) 55 lb 25° 11" 40 lb 60 lb-f 80 lb 17" 14" X y
If each of the force system shown is reduced to a force-couple system with the force acting at A, which force systems are equivalent? 400 N 200 N-m 400 N 200 N 4 m (a) (d) SCO N 200 N 2300 N.m A 1800 N.m 800 N 200 N.m 2400 N-m 4000 N-m 600 N 400 N 300 N (b) (e) (h) 900 N-m A 200 N 400 N.m 300 N D 300 N-m 300 N 300 N-m 800 N (c) (f) 900 N 4500 N.m 300 N-m 200 N
The figure below shows three forces of 20 lb each applied to a rectangular block1. Reduce the three forces to a single force and a single couple at the origin O2. Can the system be reduced to a single force? Please explain your answer3. Can the system be reduced to a single couple? Please explain your answer
3.2 Two forces and a couple are applied to the beam in an attempt to lift it. Replace this force system by an equivalent force-couple system with the force acting at (a) point A; and (b) point B. 2m 36 kN b 3 m 20 kN 2 m B 94 kN-m X
Replace the two forces in the figure below with a single force at point A and a pair whose forces act on the two points A and B
Q3: Replace the force and couple system shown in figure by an equivalent force and couple moment acting at: 400 N 1-Point A, 2-Point B 3 m 1.5m (Ans. Ma=465 N.m c.c.w., Me=575 N.m c.w) 150 N 150 N 1m 125 m
F1 F2 a F3 A d. F4 Consider the following values: F5 a = 25 m;b = 5 m; c = 25 m; d = 5 m; F1 = 3 kN; F2 = 11 kN; F3 = 2 kN; F4 = 20 kN; F5 = 2 kN; a = 30°, 0 = 60° , B = 30° 1] What is the resultant moment of the five forces acting on the rod about point A? a) - 15.8 kN.m b) 12.7 kN.m c) - 74.6 kN.m d) 52.9 kN.m e) 24.1 kN.m f)- 47.1 kN.m 2] What is the resultant moment of the five forces acting on the rod about point B? a) 8.8 kN.m b) 2.7 kN.m c) 31.6 kN.m d) 8.9 kN.m e) 5.4 kN.m ) 24.2 kN.m 3] What is the resultant moment of the five forces acting on the rod about point C? a) 86.7 kN.m b) 51.1 kN.m c) 14.6 kN.m d) 27.9 kN.m e) 74.1 kN.m ) 35.3 kN.m 4] What is the resultant moment of the five forces acting on the rod about point D? a) - 17.8 kN.m b) 82.7 kN.m c) - 21.9 kN.m d) 36.9 kN.m e) - 27.1 kN.m f) 30.1 kN.m Activate V 5] What is the moment of the force F2 about point E? Go to Setting ) 321.3 kN.m a) 111.7 kN.m b) 218.1 kN.m c) 254.6 kN.m d) 93.1 kN.m e) 101.1 kN.m bo

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3.2 Replace the force system acting on the beam by an equivalent force-couple system with the force acting at (a) point A; and (b) point B. 36 kN У 94 kN m х B 2 m 2 m 3 m 16 kN 20 kN Figure P3.2