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3.2 Problems The linear systems in Problems 1-10 are in echelon form. Solve each by back substitution. 1. x1 + x2 + 2x3 = 5 x2 + 3x3 = 6 x3 = 2 3. x₁ - 3x2 + 4x3 = 7 x2 - 5x3 = 2 5. x1 + x2 - 2x3 + x4 = 9 X2 X3 + 2x4 = 1 x3 - 3x4 = 5 2. 2x1 - 5x2 + x3 = 2 3x22x3 = 9 x3 = -3 4. x1 - 5x2 + 2x3 = 10 X2 - 7x3 = 5 6. x12x2 + 5x3 - 3x4 = x2-3x3 + 2x4 = 3 7 X4 = -4

3.2 Problems The linear systems in Problems 1-10 are in echelon form. Solve each by back substitution. 1. x1 + x2 + 2x3 = 5 x2 + 3x3 = 6 x3 = 2 3. x₁ - 3x2 + 4x3 = 7 x2 - 5x3 = 2 5. x1 + x2 - 2x3 + x4 = 9 X2 X3 + 2x4 = 1 x3 - 3x4 = 5 2. 2x1 - 5x2 + x3 = 2 3x22x3 = 9 x3 = -3 4. x1 - 5x2 + 2x3 = 10 X2 - 7x3 = 5 6. x12x2 + 5x3 - 3x4 = x2-3x3 + 2x4 = 3 7 X4 = -4

Calculus: Early Transcendentals
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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3.2 Problems The linear systems in Problems 1-10 are in echelon form. Solve each by back substitution. 1. x1 + x2 + 2x3 = 5 x2 + 3x3 = 6 x3 = 2 3. x13x2 + 4x3 = 7 x2 - 5x3 = 2 5. x1 + x2 - 2x3 + x4 = 9 X2 X3 + 2x4 = 1 x3 - 3x4 = 5 - 6. x12x2 + 5x3 3x4 = x2 3x3 + 2x4 = - - 2. 2x1 - 5x2 + x3 = 7 3 X4 = -4 2 3x22x3 = 9 x3 = -3 4. x15x2 + 2x3 = 10 x2 - 7x3 = 5
Transcribed Image Text:3.2 Problems The linear systems in Problems 1-10 are in echelon form. Solve each by back substitution. 1. x1 + x2 + 2x3 = 5 x2 + 3x3 = 6 x3 = 2 3. x13x2 + 4x3 = 7 x2 - 5x3 = 2 5. x1 + x2 - 2x3 + x4 = 9 X2 X3 + 2x4 = 1 x3 - 3x4 = 5 - 6. x12x2 + 5x3 3x4 = x2 3x3 + 2x4 = - - 2. 2x1 - 5x2 + x3 = 7 3 X4 = -4 2 3x22x3 = 9 x3 = -3 4. x15x2 + 2x3 = 10 x2 - 7x3 = 5
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