3.15. The three-phase power and line-line ratings of the electric power system shown in Figure 3.34 are given below. Ti V₂ OBE G FIGURE 3.34 1 Line 2 T2 Vm 38 M
3.15. The three-phase power and line-line ratings of the electric power system shown in Figure 3.34 are given below. Ti V₂ OBE G FIGURE 3.34 1 Line 2 T2 Vm 38 M
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
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
Transcribed Image Text:3.15. The three-phase power and line-line ratings of the electric power system
shown in Figure 3.34 are given below.
Τ
V₂
OBE
G
1
FIGURE 3.34
One-line diagram for Problem 3.15
G₁: 60 MVA
T₁:
50 MVA
50 MVA
T2:
M: 43.2 MVA
Line:
Line
20 kV
20/200 kV
200/20 kV
18 KV
200 kV
2
X = 9%
X = 10%
X = 10%
X = 8%
Z= 120+ j200
T2
38
Vm
M
(a) Draw an impedance diagram showing all impedances in per-unit on a
100-MVA base. Choose 20 kV as the voltage base for generator.

Transcribed Image Text:d)
TRANSFORMER ANALYSIS
Type of parameters for input
To obtain equivalent circuit from tests
To input individual winding impedances
To input transformer equivalent impedance
To quit
Select number of menu --> 2
Shunt branch ref. to LV side Shunt branch ref. to HV side
Rc = 10.000 ohm Rc = 1000.000 ohm
Xm = 15.000 ohm Xm = 1500.000 ohm
Enter Transformer rated power in kVA, S = 150
Enter rated low voltage in volts = 240
Enter rated high voltage in volts = 2400
Enter LV winding series impedance R1+j*X1 in ohm=0.002+j*.0045
Enter HV winding series impedance R2+j*X2 in ohm=0.2+j*0.45
Enter 'Iv' within quotes for low side shunt branch or
enter 'hv' within quotes for high side shunt branch -> 'hv'
Shunt resistance in ohm (if neglected enter inf) = 1000
Shunt reactance in ohm (if neglected enter inf) = 1500
Series branch ref. to LV side Series branch ref.to HV side
Ze = 0.0040 + j 0.0090 ohm Ze = 0.4000 + j 0.90 ohm
Select
Hit return to continue
Enter load KVA, S2 = 150
Enter load power factor, pf = 0.8
1230
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