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3.123 Air is confined to one side of a rigid container divided by a partition, as shown in Fig. P3.123. The other side is in tially evacuated. The air is initially at P 5 bar, T 500K and V, 0.2 m. When the partition is removed, the air expands to fill the entire chamber. Measurements show thes Va 2 V and P2= P/4. Assuming the air behaves as ideal gas, determine (a) the final temperature, in K and (b) th heat transfer, kJ.

3.123 Air is confined to one side of a rigid container divided by a partition, as shown in Fig. P3.123. The other side is in tially evacuated. The air is initially at P 5 bar, T 500K and V, 0.2 m. When the partition is removed, the air expands to fill the entire chamber. Measurements show thes Va 2 V and P2= P/4. Assuming the air behaves as ideal gas, determine (a) the final temperature, in K and (b) th heat transfer, kJ.

Elements Of Electromagnetics
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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3.123 Air is confined to one side of a rigid container divided by a partition, as shown in Fig. P3.123. The other side is in tially evacuated. The air is initially at p 5 bar, T,= s0K and V 0.2 m. When the partition is removed, the air expands to fill the entire chamber. Measurements show he V 2 V and p2=Pi/4. Assuming the air behaves as a ideal gas, determine (a) the final temperature, in K, and (b) the heat transfer, kJ. Remo vable partition =02 m² S bar 00 K Initially: Vacuu m Va- 2v, P2 PA Finallyy=
Transcribed Image Text:3.123 Air is confined to one side of a rigid container divided by a partition, as shown in Fig. P3.123. The other side is in tially evacuated. The air is initially at p 5 bar, T,= s0K and V 0.2 m. When the partition is removed, the air expands to fill the entire chamber. Measurements show he V 2 V and p2=Pi/4. Assuming the air behaves as a ideal gas, determine (a) the final temperature, in K, and (b) the heat transfer, kJ. Remo vable partition =02 m² S bar 00 K Initially: Vacuu m Va- 2v, P2 PA Finallyy=
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