3.12. An AM modulator is operating with an index of 0.7. The modulation input is m(t)=2 cos (2n fmt) + cos (47 fmt) +2 cos (10x fl) (a) Sketch the spectrum of the modulator output showing the weights of all impulse functions. (b) What is the efficiency of the modulation process?

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3.12. An AM modulator is operating with an index of
0.7. The modulation input is
m(t)=2 cos (27 fmt) + cos (4x fmt) +2 cos (10zx fl)
(a) Sketch the spectrum of the modulator output
showing the weights of all impulse functions.
(b) What is the efficiency of the modulation process?
Transcribed Image Text:3.12. An AM modulator is operating with an index of 0.7. The modulation input is m(t)=2 cos (27 fmt) + cos (4x fmt) +2 cos (10zx fl) (a) Sketch the spectrum of the modulator output showing the weights of all impulse functions. (b) What is the efficiency of the modulation process?
Expert Solution
Step 1: what is given and what to do:

Given:

a message signal 

m open parentheses t close parentheses equals 2 cos open parentheses 2 straight pi straight f subscript straight m straight t close parentheses plus cos open parentheses 4 straight pi straight f subscript straight m straight t close parentheses plus 2 cos open parentheses 10 straight pi straight f subscript straight m straight t close parentheses

is provided as input to the AM modulator with modulation index,m subscript a equals 0.7

To do:

a) Sketch the spectrum of the modulated signal showing the weights of all impulses. 

b) Find the efficiency of the modulation process. 



Note:

As the carrier signal is not mentioned, we need to assume it as 

c open parentheses t close parentheses equals cos open parentheses omega subscript c t close parentheses comma
text where, end text space omega subscript c greater than omega subscript m space o r space f subscript c less than f subscript m.

steps

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