绘图编辑3.12 For a strip foundation, the width is 1.2m, buried depth is 1.2m, thestandard value of the load applied on the foundation F=155KN/m, thesoil layer is distributed as follows: from the ground to the depth of 1.2m isthe land fill, =18KN/m³; the depth in the range of 1.2~1.8m is silty clay,fak=155kPa, E,=8.1Mpa, y=19KN/m³; below the depth of 1.8m is themucky clay, fak=102kPa, E,=2.7Mpa. Try to check the base pressure andthe bearing capacity of the weak sub-layer.GroundF=155KN/mOLand fill 18KN/m³1.2mO Silty clayLa-155kPa;E-8.1Mpa;y-19KN/m³-0, 1.0O Mucky clay-0, H1.0Sak-102kPa;E,-2.7Mpa1.2m

Among the most common foundations are strip foundations. Their use is generally restricted to soils…

Answered: 3.12 For a strip foundation, the width…

Principles of Foundation Engineering (MindTap Course List)

8th Edition

ISBN:9781305081550

Author:Braja M. Das

Publisher:Braja M. Das

Chapter5: Ultimate Bearing Capacity Of Shallow Foundations: Special Cases

Section: Chapter Questions

Problem 5.5P

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A 300 mm 450 mm plate was used in carrying out a plate loading test in a sand, during which the plate settled 5 mm under the applied pressure of 250 kN/m2. a. What is the coefficient of subgrade reaction for a 300 mm wide square plate? b. What would be the coefficient of subgrade reaction of a 2 m 3 m foundation?
A foundation (Figure 1) transmits a stress of 100 kPa on the surface of a soil deposit. a. Evaluate increases of vertical stresses points A, B, and C at the depth of 2m and Sm (2 points) b. At what depth is the increase in vertical stress below A less than 10% of the surface stress? 6 m +2 m- A 2 m -4 m- Figure 1: Plan of foundation
Estimate the increase in vertical stress at 0.5 m depth intervals, within the clay layer, below point A (See figure below). The foundation exerts a uniform vertical stress of 120 kPa at ground level. Using these values estimate the settlement due to the clay layer. (Hand in any graphs used) 5m 5m 2m 3m Very Dense Sand 2m 1.5m Clay E=3.5 MPa 2m Bedrock Soil profile A Plan of building 3m Soil profile and plan for Question 4 3m FA
= Figure 2 shows a rectangular shallow foundation. The foundation measures 1.5 m x3 m (B x L) in plan. The clay layer is normally consolidated with: Ce=0.27; He 3 m; e 0.92; average effective stress on the clay layer due to applied foundation load Ao=24 kN/m². Determine the primary consolidation settlement of the foundation. Sand Y = 16.5 kN/m³ Sand Yat 17.8 kN/m³ Normally consolidated clay Ysat 18.2 kN/m³ = 0.92; C = 0.27 170 kN/m² 1m 1.5 m Ground water table --- --- 15 m 3 m
A vertical column load, P = 600 kN, is applied to a rigid square concrete foundation. The foundation rests at a depth Df= 0.75 m on a uniform dense sand with the following properties: average modulus of elasticity, Es = 20,600 kN/m², and Poisson's ratio, µs = 0.3. Calculate the required foundation dimensions if the allowable settlement under the center of the foundation is 25mm. 600 kN Foundation 0.75 m Вхв Soil Hs = 0.3 E, = 20, 600 kN/m² 5.0 m Rock
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A plan of a foundation 1 m x 2 m is shown in Figure 4-2. a. Estimate the consolidation settlement of the foundation. b. Refer to part a. Given for the clay layer: Ca=0.02. Estimate the total consolidation settlement eight years after the completion of the primary consolidation settlement. (Note: Time for completion of primary consolidation settlement is 1.5 years). 15m 0.5 m 9=170 kN/m²(net stress increase) BXL 1m x 2m Sand Y = 16.5 kN/m Groundwater table Sand 25m Figure 4-2 = You 17.5 kN/m³ Normally consolidated clay y = 16 kN/m³ ea 0.78 E = 6,000 kN/m² C, = 0.32 C₁ = 0.09 A. = 0.5
2) A rectangular (5ft by 8ft) foundation will be built on the soil profile shown in the figure. Calculate the primary consolidation settlement below the center of the foundation. Assume the clay layer shown in the figure is normally consolidated. For simplicity, do not subdivide the clay into multiple sublayers. AG = 1500 lb/ft? Dry sand *120 pet Clay,Ce =0.28 e,= 0.55 Ya 125 pct Bedrock (Impermeable)
Estimate the ultimate consolidation settlement under the centerline of a 25 x 25 meter mat foundation. The mat is 1.5 meter thick reinforced concrete (ϒconcrete = 23.6 kN / m3), and the average stress on the surface of the slab is 125 kPa. The soil profile is shown in the figure below. Lab testing on samples of the clay showed that the clay is normally consolidated and that Cc = 0.40, Cr = 0.03, and eo = 1.13. Neglect any settlements due to the sand layer. Divide the clay layer into four thinner layers of thickness 2.0, 2.0, 3.0, and 3.0 meters.
Problem 2. Determine the average (top, middle, and bottom) stress increase in the clay layer below the center of foundation due to foundation load of 50 tons. 50 ton (net load) Sand 100 Ib/ 4:5 t Groupdwater table 5 ft X 5 ft *Sand 122 lb/ft 3 ft A120 Ib/ft 0.7 C, = 0.25 10 ft 0,06 Preconsolidation pressure = 2000 lb/ft?
Q 1) A concrete foundation rests on the surface of a soil mass. Determine the vertical stress increase at point A. 4 m 1 m 1.5 m PLAN 1.5 m Fondation Load 3000 KN 2 m SECTION A Soil

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