3.1 Exactly 1 litre of solution contains 0.018 mole of Ba2+ ions and 0.0018 mole of Pb2+ ions. You wish to separate these ions by selective precipitation using the drop-wise addition of a solution of K2SO4. Explain, by using a full calculation, which of the salts BaSO, or PbSO4 will precipitate first? Given: Ksp (BaS04) = 1.1 × 10-10 and Ksp (PbS04) = 1.6 × 10-8

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
icon
Related questions
Question
3.1 Exactly 1 litre of solution contains 0.018 mole of Ba?+ ions and 0.0018 mole of Pb2+ ions.
You wish to separate these ions by selective precipitation using the drop-wise addition of a
solution of K2SO4:
Explain, by using a full calculation, which of the salts BaSO4 or PbSO, will precipitate first?
Given: Kep (BaSO4) = 1.1 x 10-10 and Kep (PBSO4) = 1.6 × 10-8
3.2
A voltaic cell is set up at 25 °C and delivers 0.060 V. One half cell contains an acidified solution
of permanganate and manganese(II) ions, and the other half-cell is based on the following
reaction:
Br05 (aq) + 6H30*(aq) + 6e- → Br-(aq) + 9H20 (P), Eed = 1.44 V
3.2.1 Write down the fully balanced cell-reaction equation.
3.2.2
[Mn2+]6
What must the value of the ratio;
be if [Br03] = 0.90 M, [Br¯] = 1.11 M, and the
[MnOg]6
pH = 0.60?
Transcribed Image Text:3.1 Exactly 1 litre of solution contains 0.018 mole of Ba?+ ions and 0.0018 mole of Pb2+ ions. You wish to separate these ions by selective precipitation using the drop-wise addition of a solution of K2SO4: Explain, by using a full calculation, which of the salts BaSO4 or PbSO, will precipitate first? Given: Kep (BaSO4) = 1.1 x 10-10 and Kep (PBSO4) = 1.6 × 10-8 3.2 A voltaic cell is set up at 25 °C and delivers 0.060 V. One half cell contains an acidified solution of permanganate and manganese(II) ions, and the other half-cell is based on the following reaction: Br05 (aq) + 6H30*(aq) + 6e- → Br-(aq) + 9H20 (P), Eed = 1.44 V 3.2.1 Write down the fully balanced cell-reaction equation. 3.2.2 [Mn2+]6 What must the value of the ratio; be if [Br03] = 0.90 M, [Br¯] = 1.11 M, and the [MnOg]6 pH = 0.60?
Expert Solution
steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Knowledge Booster
Iodine Titrations
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781259911156
Author:
Raymond Chang Dr., Jason Overby Professor
Publisher:
McGraw-Hill Education
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Organic Chemistry
Organic Chemistry
Chemistry
ISBN:
9780078021558
Author:
Janice Gorzynski Smith Dr.
Publisher:
McGraw-Hill Education
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning
Elementary Principles of Chemical Processes, Bind…
Elementary Principles of Chemical Processes, Bind…
Chemistry
ISBN:
9781118431221
Author:
Richard M. Felder, Ronald W. Rousseau, Lisa G. Bullard
Publisher:
WILEY