3.00 mL of bleach (NaOCl is the active ingredient) is mixed with KI and HCl to completely form triiodide (I, ) ions. The I, ions is titrated with a 0.1306 3. 3 M thiosulfate (S,0, ) solution. The endpoint is reached when 31.52 mL of the thiosulfate solution is added. 3. The moles of sodium thiosulfate used in the reaction is? Select one: а. 0.00389 b. 0.00412 С. 0.00327 O d. 0.00462

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Which of the following adequately
describes the role of I in the reaction
with concentrated sulfuric acid?
Select one:
a. spectator ion
b. oxidising agent
c. reducing agent
d. oxidised
Transcribed Image Text:Which of the following adequately describes the role of I in the reaction with concentrated sulfuric acid? Select one: a. spectator ion b. oxidising agent c. reducing agent d. oxidised
3.00 mL of bleach (NaOCl is the active
ingredient) is mixed with KI and HCl to
completely form triiodide (I, ) ions.
The I, ions is titrated with a 0.1306
M thiosulfate (S,0," ) solution. The
3.
endpoint is reached when 31.52 mL of
the thiosulfate solution is added.
The moles of sodium thiosulfate used
in the reaction is?
Select one:
а.
0.00389
b. 0.00412
С.
0.00327
d.
0.00462
Transcribed Image Text:3.00 mL of bleach (NaOCl is the active ingredient) is mixed with KI and HCl to completely form triiodide (I, ) ions. The I, ions is titrated with a 0.1306 M thiosulfate (S,0," ) solution. The 3. endpoint is reached when 31.52 mL of the thiosulfate solution is added. The moles of sodium thiosulfate used in the reaction is? Select one: а. 0.00389 b. 0.00412 С. 0.00327 d. 0.00462
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