-3.0 X 10-6 C 4.0 X 10-6 C 5.0 X 10-6 C (b) a a -2.0 X 10-6 C (c) End cap of area 4.0 X 10–4 m2 o = 2.0 × 10-6 C/m? + + + + + + + 8 - 8. Conductor + + + + + + +

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Find the electric flux through the closed surface whose cross-sections are below.

-3.0 X 10-6 C
4.0 X 10-6 C
5.0 X 10-6 C
(b)
a
а
-2.0 X 10-6 C
(c)
End cap
of area
4.0 X 10-4 m²
o = 2.0 × 10-6 C/m²
(d)
+ + + + + + +
8
Conductor
+ + + + + + +
Transcribed Image Text:-3.0 X 10-6 C 4.0 X 10-6 C 5.0 X 10-6 C (b) a а -2.0 X 10-6 C (c) End cap of area 4.0 X 10-4 m² o = 2.0 × 10-6 C/m² (d) + + + + + + + 8 Conductor + + + + + + +
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