3. You perform an alkalinity test on a water sample with an initial pH of 9.75. The alkalinity is 12.1 mg/L as CaCO3. (a) Calculate the CT value. Answer: 1.54×10-4 M (b) Determine whether there is any potential to precipitate CaCO3 in the pipes given a calcium concentration of 15 mg/L. Justify your answer. Answer: Calculations show that it exceeds the Ksp, so yes there is a potential. (c) For the same calcium concentration and CT, determine the potential to precipitate CaCO3 if the pH were to be lowered to 7. Answer: No, but why? Show calculations to support your answer.
3. You perform an alkalinity test on a water sample with an initial pH of 9.75. The alkalinity is 12.1 mg/L as CaCO3. (a) Calculate the CT value. Answer: 1.54×10-4 M (b) Determine whether there is any potential to precipitate CaCO3 in the pipes given a calcium concentration of 15 mg/L. Justify your answer. Answer: Calculations show that it exceeds the Ksp, so yes there is a potential. (c) For the same calcium concentration and CT, determine the potential to precipitate CaCO3 if the pH were to be lowered to 7. Answer: No, but why? Show calculations to support your answer.
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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3. You perform an alkalinity test on a water sample with an initial pH of 9.75. The alkalinity is 12.1
mg/L as CaCO3.
(a) Calculate the CT value. Answer: 1.54×10-4 M
(b) Determine whether there is any potential to precipitate CaCO3 in the pipes given a calcium
concentration of 15 mg/L. Justify your answer. Answer: Calculations show that it exceeds the Ksp, so yes
there is a potential.
(c) For the same calcium concentration and CT, determine the potential to precipitate CaCO3 if the pH
were to be lowered to 7. Answer: No, but why? Show calculations to support your answer.
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