3. You have a reaction that is run at 273°C and has a rate constant of 2.52 x 10/s. The same reaction is run at 157 °C and has a rate constant of 1.0 x 10-/s. What is the activation energy for this reaction? (R = 8.314 J/mol K) O.00898 mols 102 sec
3. You have a reaction that is run at 273°C and has a rate constant of 2.52 x 10/s. The same reaction is run at 157 °C and has a rate constant of 1.0 x 10-/s. What is the activation energy for this reaction? (R = 8.314 J/mol K) O.00898 mols 102 sec
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![3.
You have a reaction that is run at 273°C and has a rate constant of 2.52 x 10/s. The same
reaction is run at 157 °C and has a rate constant of 1.0 x 10-/s. What is the activation energy for this
reaction? (R = 8.314 J/mol K)
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0.00898mols
102 sec
4.
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ate= k[NO2]?. The rate constant for this reaction:
If
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urd be the concentra](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff35f8f89-65fc-4b90-98e9-68f8eaa1b3da%2Fd00d995d-4993-4e7f-978b-c697140e68e6%2F8d01i5_processed.jpeg&w=3840&q=75)
Transcribed Image Text:3.
You have a reaction that is run at 273°C and has a rate constant of 2.52 x 10/s. The same
reaction is run at 157 °C and has a rate constant of 1.0 x 10-/s. What is the activation energy for this
reaction? (R = 8.314 J/mol K)
%3D
0.00898mols
102 sec
4.
w for
ate= k[NO2]?. The rate constant for this reaction:
If
yo
tion for 5 minutes
urd be the concentra
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