3. You currently drive 240 miles per week in a car that gets 16 miles per gallon. A new car cost $13,000 (after trade-in) and gets 40 miles per gallon. Insurance and repairs for the old car are $600 per year and $1400 per year, respectively. The insurance for the new car is $800 per year and there are no repair costs for the first 5 years. Assume gas costs $3.50 per gallon for the next 5 years. (a) What is the cost of keeping your old car for the next 5 years? (b) What is the cost of the new car for the next 5 years? (c) How much money might you save by choosing the less expensive option?

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ChapterP: Prerequisites: Fundamental Concepts Of Algebra
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Currently drive 240 miles per week in a car they get 16 miles per gallon. A new car cost $13,000…. (See photo)
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### Cost Analysis of Keeping an Old Car vs. Buying a New Car

#### Problem Statement:
You currently drive 240 miles per week in a car that gets 16 miles per gallon. A new car costs $13,000 (after trade-in) and gets 40 miles per gallon. Insurance and repairs for the old car are $600 per year and $1400 per year, respectively. The insurance for the new car is $800 per year and there are no repair costs for the first 5 years. Assume gas costs $3.50 per gallon for the next 5 years.

**(a) What is the cost of keeping your old car for the next 5 years?**

**(b) What is the cost of the new car for the next 5 years?**

**(c) How much money might you save by choosing the less expensive option?**

#### Solution:

**(a) Cost of Keeping the Old Car for the Next 5 Years**

1. **Fuel Costs**:
   - Weekly miles driven = 240 miles
   - Miles per gallon for old car = 16 MPG
   - Cost per gallon of gas = $3.50
   
   \[
   \text{Fuel consumed per week} = \frac{240 \text{ miles}}{16 \text{ MPG}} = 15 \text{ gallons/week}
   \]
   
   \[
   \text{Cost of fuel per week} = 15 \text{ gallons/week} \times \$3.50/\text{gallon} = \$52.50/\text{week}
   \]
   
   \[
   \text{Annual fuel cost} = \$52.50/\text{week} \times 52 \text{ weeks/year} = \$2730/year
   \]
   
   \[
   \text{Cost over 5 years} = \$2730/year \times 5 \text{ years} = \$13650
   \]

2. **Insurance Costs**:
   \[
   \text{Yearly insurance cost} = \$600/year
   \]
   
   \[
   \text{5-year insurance cost} = \$600/year \times 5 \text{ years} = \$3000
   \]

3. **Repair Costs**:
   \[
   \text{Yearly repair cost} = \$1400/year
   \]
Transcribed Image Text:--- ### Cost Analysis of Keeping an Old Car vs. Buying a New Car #### Problem Statement: You currently drive 240 miles per week in a car that gets 16 miles per gallon. A new car costs $13,000 (after trade-in) and gets 40 miles per gallon. Insurance and repairs for the old car are $600 per year and $1400 per year, respectively. The insurance for the new car is $800 per year and there are no repair costs for the first 5 years. Assume gas costs $3.50 per gallon for the next 5 years. **(a) What is the cost of keeping your old car for the next 5 years?** **(b) What is the cost of the new car for the next 5 years?** **(c) How much money might you save by choosing the less expensive option?** #### Solution: **(a) Cost of Keeping the Old Car for the Next 5 Years** 1. **Fuel Costs**: - Weekly miles driven = 240 miles - Miles per gallon for old car = 16 MPG - Cost per gallon of gas = $3.50 \[ \text{Fuel consumed per week} = \frac{240 \text{ miles}}{16 \text{ MPG}} = 15 \text{ gallons/week} \] \[ \text{Cost of fuel per week} = 15 \text{ gallons/week} \times \$3.50/\text{gallon} = \$52.50/\text{week} \] \[ \text{Annual fuel cost} = \$52.50/\text{week} \times 52 \text{ weeks/year} = \$2730/year \] \[ \text{Cost over 5 years} = \$2730/year \times 5 \text{ years} = \$13650 \] 2. **Insurance Costs**: \[ \text{Yearly insurance cost} = \$600/year \] \[ \text{5-year insurance cost} = \$600/year \times 5 \text{ years} = \$3000 \] 3. **Repair Costs**: \[ \text{Yearly repair cost} = \$1400/year \]
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