3. You are in the laboratory and measure the initial rate of an enzyme reaction as a function of substrate concentration in the presence and absence of an inhibitor. You obtain the following data: Vo, + inhibitor, [Substrate], mM Vo, - inhibitor, (μM/min) (μM/min) 0.0001 33 17 0.0002 50 29 0.0005 71 50 0.001 83 67 0.002 91 80 0.005 96 91 0.01 98 95 0.02 99 98 0.05 100 99 0.1 100 100 0.1 100 100 (a) What is the Vmax in the absence of inhibitor? (b) What is the Km in the absence of inhibitor?
3. You are in the laboratory and measure the initial rate of an enzyme reaction as a function of substrate concentration in the presence and absence of an inhibitor. You obtain the following data: Vo, + inhibitor, [Substrate], mM Vo, - inhibitor, (μM/min) (μM/min) 0.0001 33 17 0.0002 50 29 0.0005 71 50 0.001 83 67 0.002 91 80 0.005 96 91 0.01 98 95 0.02 99 98 0.05 100 99 0.1 100 100 0.1 100 100 (a) What is the Vmax in the absence of inhibitor? (b) What is the Km in the absence of inhibitor?
Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
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ANSWER A AND B PLS
![3. You are in the laboratory and measure the initial rate of an enzyme reaction as a function of substrate
concentration in the presence and absence of an inhibitor. You obtain the following data:
Vo, + inhibitor,
[Substrate], mM
Vo, - inhibitor,
(μM/min)
(μM/min)
0.0001
33
17
0.0002
50
29
0.0005
71
50
0.001
83
67
0.002
91
80
0.005
96
91
0.01
98
95
0.02
99
98
0.05
100
99
0.1
100
100
0.1
100
100
(a) What is the Vmax in the absence of inhibitor?
(b) What is the Km in the absence of inhibitor?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd6957468-6fb1-4659-9083-987b06676d6d%2F5028a613-dbc3-4daa-af86-8ec2a845d55b%2F77oh5pr_processed.png&w=3840&q=75)
Transcribed Image Text:3. You are in the laboratory and measure the initial rate of an enzyme reaction as a function of substrate
concentration in the presence and absence of an inhibitor. You obtain the following data:
Vo, + inhibitor,
[Substrate], mM
Vo, - inhibitor,
(μM/min)
(μM/min)
0.0001
33
17
0.0002
50
29
0.0005
71
50
0.001
83
67
0.002
91
80
0.005
96
91
0.01
98
95
0.02
99
98
0.05
100
99
0.1
100
100
0.1
100
100
(a) What is the Vmax in the absence of inhibitor?
(b) What is the Km in the absence of inhibitor?
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