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3. Yield and Selectivity: Consider a more complex version of the process from #2 (see diagram top of next page), in which a second undesired reaction occurs, where the desired product ethylbenzene further reacts with an ethylene molecule to form the undesired product diethylbenzene. Calculate the yield and selectivity, based on the ethylbenzene being the desired product, and the diethylbenzene being the undesired product. RXN 1: Benzene (BZ) + Ethylene (ET) → Ethylbenzene (EB) CoHo + CH 7 CoHsC,Hs RXN 2: Ethylbenzene (EB) + Ethylene (ET) → Diethylbenzene (DEB) CH5C₂H5 + C₂H4 → C6H5(C₂H5)₂ = 200 mol BZ nBz,0 NET,O=300 mol ET Reaction Process nвz = 50 mol BZ NET = 120 mol ET nEB 120 mol EB nDEB = 30 mol DEB

3. Yield and Selectivity: Consider a more complex version of the process from #2 (see diagram top of next page), in which a second undesired reaction occurs, where the desired product ethylbenzene further reacts with an ethylene molecule to form the undesired product diethylbenzene. Calculate the yield and selectivity, based on the ethylbenzene being the desired product, and the diethylbenzene being the undesired product. RXN 1: Benzene (BZ) + Ethylene (ET) → Ethylbenzene (EB) CoHo + CH 7 CoHsC,Hs RXN 2: Ethylbenzene (EB) + Ethylene (ET) → Diethylbenzene (DEB) CH5C₂H5 + C₂H4 → C6H5(C₂H5)₂ = 200 mol BZ nBz,0 NET,O=300 mol ET Reaction Process nвz = 50 mol BZ NET = 120 mol ET nEB 120 mol EB nDEB = 30 mol DEB

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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Benzene (BZ) + Ethylene (ET) ➜ Ethylbenzene (EB) C₂H6 + C₂H4 → C6H5C₂H5 nBZ,0 = 100 mol BZ nET,O = 80 mol ET Reaction Process 3. Yield and Selectivity: Consider a more complex version of the process from #2 (see diagram top of next page), in which a second undesired reaction occurs, where the desired product ethylbenzene further reacts with an ethylene molecule to form the undesired product diethylbenzene. Calculate the yield and selectivity, based on the ethylbenzene being the desired product, and the diethylbenzene being the undesired product. = 200 mol BZ nBZ,0 NET,O=300 mol ET nBZ = 40 Mol BZ nET = 20 mol ET nEB = 60 mol EB RXN 1: Benzene (BZ) + Ethylene (ET) → Ethylbenzene (EB) C₂H₂ + C₂H4 → CHC₂H5 RXN 2: Ethylbenzene (EB) + Ethylene (ET) → Diethylbenzene (DEB) CH5C₂H5 + C₂H² → C6H5(C₂H5)2 Reaction Process nBz = 50 mol BZ NET = 120 mol ET nEB = 120 mol EB nDEB = 30 mol DEB
Transcribed Image Text:Benzene (BZ) + Ethylene (ET) ➜ Ethylbenzene (EB) C₂H6 + C₂H4 → C6H5C₂H5 nBZ,0 = 100 mol BZ nET,O = 80 mol ET Reaction Process 3. Yield and Selectivity: Consider a more complex version of the process from #2 (see diagram top of next page), in which a second undesired reaction occurs, where the desired product ethylbenzene further reacts with an ethylene molecule to form the undesired product diethylbenzene. Calculate the yield and selectivity, based on the ethylbenzene being the desired product, and the diethylbenzene being the undesired product. = 200 mol BZ nBZ,0 NET,O=300 mol ET nBZ = 40 Mol BZ nET = 20 mol ET nEB = 60 mol EB RXN 1: Benzene (BZ) + Ethylene (ET) → Ethylbenzene (EB) C₂H₂ + C₂H4 → CHC₂H5 RXN 2: Ethylbenzene (EB) + Ethylene (ET) → Diethylbenzene (DEB) CH5C₂H5 + C₂H² → C6H5(C₂H5)2 Reaction Process nBz = 50 mol BZ NET = 120 mol ET nEB = 120 mol EB nDEB = 30 mol DEB
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