3. - y = 5 with zero initial conditions (i.e. y(0) dy(0) = dt dºy(0) 'y(0) -0) %3D %3D Answer: y(t) = je-t + fe' + cos t – 5
3. - y = 5 with zero initial conditions (i.e. y(0) dy(0) = dt dºy(0) 'y(0) -0) %3D %3D Answer: y(t) = je-t + fe' + cos t – 5
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Transcribed Image Text:3. 4 - y = 5 with zero initial conditions (i.e. y(0) =
dy(0)
dt
dy(0)
fy0) = 0)
di
IP
Answer: y(t) = je=t + §et + cos t – 5
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