3. x + 3x + 2x = 0 %3D a. Good guesses: b. # of positive roots: c. # of negative roots: d. # of imaginary roots: e. upper bound f. lower bound g. answers:

Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Find the zeros of the following polynomials by using the following aids.
Use the rational zero theorem, Descartes's rule of signs, and the theorem on bounds as aids in finding
all real and imaginary roots to each equation.
htt(h-)のでtz(h-)6+c(h-)
X4,-3,-2 are
1. x + 9x? + 26x + 24 = 0
a. Good guesses:
the roots Of epho
b. # of positive roots:
c. # of negative roots:
d. # of imaginary roots:
K+4) x 3+ 9x2+26x+24 (x2+5xt0 "" -ve" -3
X 3
e. upper bound
f. lower bound
+4x2
there Is no bound
5x²+20x+24 (x+4)(x?+5x+e)=ouince lim fA) e
g. answers:
xQしtzXg
6.
6x+24
2. 2x3-7x2 – 16= 0
B The root of the equaionis
a. Good guesses:
Q-01-zメL-×t
There are no negatNe
b. # of positive roots:
c. # of negative roots:
d. # of imaginary roots:
s4009-の1-×hとメhてメナ。メて
D. the
Oこの1-メーローメhtzメ+をメt
bound
3(htメtz×2) (h-X)
the tanation is -
e. upper
f. lower bound
imaginary rootof
hりe
g. answers:
Lhこx
zvて(1E- こX
3. x + 3x³ + 2x = 0
a. Good guesses:
b. # of positive roots:
c. # of negative roots:
d. # of imaginary roots:
e. upper bound
f. lower bound
g. answers:
-ニzX
!4こX
Transcribed Image Text:Find the zeros of the following polynomials by using the following aids. Use the rational zero theorem, Descartes's rule of signs, and the theorem on bounds as aids in finding all real and imaginary roots to each equation. htt(h-)のでtz(h-)6+c(h-) X4,-3,-2 are 1. x + 9x? + 26x + 24 = 0 a. Good guesses: the roots Of epho b. # of positive roots: c. # of negative roots: d. # of imaginary roots: K+4) x 3+ 9x2+26x+24 (x2+5xt0 "" -ve" -3 X 3 e. upper bound f. lower bound +4x2 there Is no bound 5x²+20x+24 (x+4)(x?+5x+e)=ouince lim fA) e g. answers: xQしtzXg 6. 6x+24 2. 2x3-7x2 – 16= 0 B The root of the equaionis a. Good guesses: Q-01-zメL-×t There are no negatNe b. # of positive roots: c. # of negative roots: d. # of imaginary roots: s4009-の1-×hとメhてメナ。メて D. the Oこの1-メーローメhtzメ+をメt bound 3(htメtz×2) (h-X) the tanation is - e. upper f. lower bound imaginary rootof hりe g. answers: Lhこx zvて(1E- こX 3. x + 3x³ + 2x = 0 a. Good guesses: b. # of positive roots: c. # of negative roots: d. # of imaginary roots: e. upper bound f. lower bound g. answers: -ニzX !4こX
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