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3. Without using the formula for the 1-segment trapezoidal rule for estimating f(x)dx the true error E, can be found directly as well as exactly by using the formula a) f(x) = ex b) f(x)=x+3x c) f(x)=5x²+3 d) f(x)=5x²+e* (b-a)³ E₁-- f"). assb 12 4. Let X-ẞ (4,0.3), then a) = 1, 82=0.84 b)=1.2, 82 = 0.84 c) = 1.2, 82 = 0.21 = 1.2, 82 = 2.8 5. Let X1, X2, X N (1,82). then a) X~N (82) b) -N (0.1) c)√√N (0,1)

3. Without using the formula for the 1-segment trapezoidal rule for estimating f(x)dx the true error E, can be found directly as well as exactly by using the formula a) f(x) = ex b) f(x)=x+3x c) f(x)=5x²+3 d) f(x)=5x²+e* (b-a)³ E₁-- f"). assb 12 4. Let X-ẞ (4,0.3), then a) = 1, 82=0.84 b)=1.2, 82 = 0.84 c) = 1.2, 82 = 0.21 = 1.2, 82 = 2.8 5. Let X1, X2, X N (1,82). then a) X~N (82) b) -N (0.1) c)√√N (0,1)

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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3. Without using the formula for the 1-segment trapezoidal rule for estimating f(x)dx the true error E, can be found directly as well as exactly by using the formula a) f(x) = ex b) f(x)=x+3x c) f(x)=5x²+3 d) f(x)=5x²+e* (b-a)³ E₁-- f"). assb 12 4. Let X-ẞ (4,0.3), then a) = 1, 82=0.84 b)=1.2, 82 = 0.84 c) = 1.2, 82 = 0.21 = 1.2, 82 = 2.8 5. Let X1, X2, X N (1,82). then a) X~N (82) b) -N (0.1) c)√√N (0,1)
Transcribed Image Text:3. Without using the formula for the 1-segment trapezoidal rule for estimating f(x)dx the true error E, can be found directly as well as exactly by using the formula a) f(x) = ex b) f(x)=x+3x c) f(x)=5x²+3 d) f(x)=5x²+e* (b-a)³ E₁-- f"). assb 12 4. Let X-ẞ (4,0.3), then a) = 1, 82=0.84 b)=1.2, 82 = 0.84 c) = 1.2, 82 = 0.21 = 1.2, 82 = 2.8 5. Let X1, X2, X N (1,82). then a) X~N (82) b) -N (0.1) c)√√N (0,1)
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