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3. Which solution is more concentrated? Justify your answer with calculations. OR 00.g of C12H22O11(s) in 500.mL of C12H22011(aq) 50.0g of NaCl(s) in 250.mL of NaCl(aq) 4.6752 6-84

3. Which solution is more concentrated? Justify your answer with calculations. OR 00.g of C12H22O11(s) in 500.mL of C12H22011(aq) 50.0g of NaCl(s) in 250.mL of NaCl(aq) 4.6752 6-84

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Chemistry
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ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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3. Which solution is more concentrated? Justify your answer with calculations. 50.0g of NaCl(s) in 250.mL of NaCl(aq) OR 100.g of C12H22O11(s) in 500.mL of C12H22O11(aq) 4.6752 6-846 4. How much sucrose would you need to use to prepare a 250mL solution with equivalent concentration as the 250mL salt solution above?
Transcribed Image Text:3. Which solution is more concentrated? Justify your answer with calculations. 50.0g of NaCl(s) in 250.mL of NaCl(aq) OR 100.g of C12H22O11(s) in 500.mL of C12H22O11(aq) 4.6752 6-846 4. How much sucrose would you need to use to prepare a 250mL solution with equivalent concentration as the 250mL salt solution above?
1. Calculate how much lemonade powder you will need to make 0.100 L of each solution. Fruit drink is mostly sucrose (C₁₂H₂O₁₁), so you can assume that the "molar mass" of fruit drink is the same as the molar mass of sucrose. Mass of fruit drink needed for 0.100 M solution: Mass of fruit drink needed for 0.200 M solution: Mass of fruit drink needed for 0.400 M solution:
Transcribed Image Text:1. Calculate how much lemonade powder you will need to make 0.100 L of each solution. Fruit drink is mostly sucrose (C₁₂H₂O₁₁), so you can assume that the "molar mass" of fruit drink is the same as the molar mass of sucrose. Mass of fruit drink needed for 0.100 M solution: Mass of fruit drink needed for 0.200 M solution: Mass of fruit drink needed for 0.400 M solution:
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To determine which solution is more concentrated, we can calculate the molarity of each solution.

 

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