3. What is the gravitational potential energy of a 4 kg bowling ball 1 m above the ground?

College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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**Question 3:**
What is the gravitational potential energy of a 4 kg bowling ball 1 m above the ground?

*Note:* The question does not contain any graphs or diagrams. 

To solve this problem, use the formula for gravitational potential energy (GPE):

\[ GPE = mgh \]

Where:
- \( m \) is the mass (4 kg)
- \( g \) is the acceleration due to gravity (approximately 9.8 m/s²)
- \( h \) is the height above the ground (1 m)

Substituting these values into the formula:

\[ GPE = 4 \, \text{kg} \times 9.8 \, \text{m/s}² \times 1 \, \text{m} = 39.2 \, \text{Joules} \]

Thus, the gravitational potential energy is 39.2 Joules.
Transcribed Image Text:**Question 3:** What is the gravitational potential energy of a 4 kg bowling ball 1 m above the ground? *Note:* The question does not contain any graphs or diagrams. To solve this problem, use the formula for gravitational potential energy (GPE): \[ GPE = mgh \] Where: - \( m \) is the mass (4 kg) - \( g \) is the acceleration due to gravity (approximately 9.8 m/s²) - \( h \) is the height above the ground (1 m) Substituting these values into the formula: \[ GPE = 4 \, \text{kg} \times 9.8 \, \text{m/s}² \times 1 \, \text{m} = 39.2 \, \text{Joules} \] Thus, the gravitational potential energy is 39.2 Joules.
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