3. Using the truncated viral equation of state given below, nRT ¸ n°RTB(T) P = V . (a) Calculate the amount of work done as 500 mol of acetone (g) is compressed isothermally from 500 to 2.00 dm² at 363 K with B(T) = B(363 K) =-874 cm³ mol. (b) Next, calculate the same isothermal compression, however, in this case for 500 mol of neon (g) at 363 K whose second Virial coefficient is B(T) = B(363 K) = 12.1 cm³ mol-'. (c) Finally, compare and contrast these two values of compressive work (wmr). Speculate on why acetones result comes out the way that it does; i.e., what molecular or chemical rationale can explain its result.

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3. Using the truncated viral equation of state given below,
nRT n° RTB(T)
P =
V
.(a) Calculate the amount of work done as 500 mol of acetone (g) is compressed isothermally from 500 to
2.00 dm at 363 K with B(T) = B(363 K) =-874 cm³ mol-'.
(b) Next, calculate the same isothermal compression, however, in this case for 500 mol of neon (g) at
363 K whose second Virial coefficient is B(T) = B(363 K) = 12.1 cm³ mol-.
(c) Finally, compare and contrast these two values of compressive work (wompresion). Speculate on why
acetones result comes out the way that it does; i.e., what molecular or chemical rationale can explain its
result.
Transcribed Image Text:3. Using the truncated viral equation of state given below, nRT n° RTB(T) P = V .(a) Calculate the amount of work done as 500 mol of acetone (g) is compressed isothermally from 500 to 2.00 dm at 363 K with B(T) = B(363 K) =-874 cm³ mol-'. (b) Next, calculate the same isothermal compression, however, in this case for 500 mol of neon (g) at 363 K whose second Virial coefficient is B(T) = B(363 K) = 12.1 cm³ mol-. (c) Finally, compare and contrast these two values of compressive work (wompresion). Speculate on why acetones result comes out the way that it does; i.e., what molecular or chemical rationale can explain its result.
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