3. Use the binomial theorem to prove that 2n 2n |22n–2k = (2.5)2". k k=0

Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
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Chapter2: Second-order Linear Odes
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Use the binomial theorem to prove that 2n choose k= 2^n-2k = (2.5)^2n .

**Question 3: Application of the Binomial Theorem**

Use the binomial theorem to prove the following identity:

\[
\sum_{k=0}^{2n} \binom{2n}{k} 2^{2n-2k} = (2.5)^{2n}.
\]

**Explanation:**

- The left side of the equation involves a summation where the sum is taken from \(k = 0\) to \(k = 2n\).
- In each term of the summation, \(\binom{2n}{k}\) represents a binomial coefficient, which gives the number of ways to choose \(k\) elements from a set of \(2n\) elements.
- The term \(2^{2n-2k}\) is an exponential function that depends on the index \(k\).
- The right side of the equation is simply \((2.5)^{2n}\), indicating that the whole sum should equal this expression when simplified.

This problem requires using the binomial theorem to verify the equality of these expressions.
Transcribed Image Text:**Question 3: Application of the Binomial Theorem** Use the binomial theorem to prove the following identity: \[ \sum_{k=0}^{2n} \binom{2n}{k} 2^{2n-2k} = (2.5)^{2n}. \] **Explanation:** - The left side of the equation involves a summation where the sum is taken from \(k = 0\) to \(k = 2n\). - In each term of the summation, \(\binom{2n}{k}\) represents a binomial coefficient, which gives the number of ways to choose \(k\) elements from a set of \(2n\) elements. - The term \(2^{2n-2k}\) is an exponential function that depends on the index \(k\). - The right side of the equation is simply \((2.5)^{2n}\), indicating that the whole sum should equal this expression when simplified. This problem requires using the binomial theorem to verify the equality of these expressions.
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