3. Use the binomial theorem to prove that 2n 2n |22n–2k = (2.5)2". k k=0
Advanced Engineering Mathematics
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ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
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Use the binomial theorem to prove that 2n choose k= 2^n-2k = (2.5)^2n .
![**Question 3: Application of the Binomial Theorem**
Use the binomial theorem to prove the following identity:
\[
\sum_{k=0}^{2n} \binom{2n}{k} 2^{2n-2k} = (2.5)^{2n}.
\]
**Explanation:**
- The left side of the equation involves a summation where the sum is taken from \(k = 0\) to \(k = 2n\).
- In each term of the summation, \(\binom{2n}{k}\) represents a binomial coefficient, which gives the number of ways to choose \(k\) elements from a set of \(2n\) elements.
- The term \(2^{2n-2k}\) is an exponential function that depends on the index \(k\).
- The right side of the equation is simply \((2.5)^{2n}\), indicating that the whole sum should equal this expression when simplified.
This problem requires using the binomial theorem to verify the equality of these expressions.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F766ef7ef-e170-4433-a637-5afda4309c84%2F94efef56-9911-4a46-86eb-4b5b59e419d4%2Fb8lkhvi_processed.png&w=3840&q=75)
Transcribed Image Text:**Question 3: Application of the Binomial Theorem**
Use the binomial theorem to prove the following identity:
\[
\sum_{k=0}^{2n} \binom{2n}{k} 2^{2n-2k} = (2.5)^{2n}.
\]
**Explanation:**
- The left side of the equation involves a summation where the sum is taken from \(k = 0\) to \(k = 2n\).
- In each term of the summation, \(\binom{2n}{k}\) represents a binomial coefficient, which gives the number of ways to choose \(k\) elements from a set of \(2n\) elements.
- The term \(2^{2n-2k}\) is an exponential function that depends on the index \(k\).
- The right side of the equation is simply \((2.5)^{2n}\), indicating that the whole sum should equal this expression when simplified.
This problem requires using the binomial theorem to verify the equality of these expressions.
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