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3. Use De Moivre's Theorem to solve for the roots of : a® – 1 - j1 = 0 O A. 1 cjs (T/24 + rtk) ; k = 0, 1, 2, 3, 4, 5 O B. 1 cjs (T/24 + rtk/2) ; k = 0, 1, 2, 3, 4, 5 O C. 1 cjs (T/24 + rtk/4) ; k = 0, 1, 2, 3, 4, 5 D. 1 cjs (t/24 + tik/3) ; k = 0, 1, 2, 3, 4, 5

3. Use De Moivre's Theorem to solve for the roots of : a® – 1 - j1 = 0 O A. 1 cjs (T/24 + rtk) ; k = 0, 1, 2, 3, 4, 5 O B. 1 cjs (T/24 + rtk/2) ; k = 0, 1, 2, 3, 4, 5 O C. 1 cjs (T/24 + rtk/4) ; k = 0, 1, 2, 3, 4, 5 D. 1 cjs (t/24 + tik/3) ; k = 0, 1, 2, 3, 4, 5

Advanced Engineering Mathematics
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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Solve no.03 and show a clear and organized solution. Thanks!!!

3. Use De Moivre's Theorem to solve for the roots of : x° – 1 - j1 = 0 O A. 1 cjs (T/24 + tik) ; k = 0, 1, 2, 3, 4, 5 O B. 1 cjs (Tt/24 + Ttk/2) ; k = 0, 1, 2, 3, 4, 5 O C. 1 cjs (T/24 + Ttk/4) ; k = 0, 1, 2, 3, 4, 5 O D. 1 cjs (T/24 + Tik/3) ; k = 0, 1, 2, 3, 4, 5
Transcribed Image Text:3. Use De Moivre's Theorem to solve for the roots of : x° – 1 - j1 = 0 O A. 1 cjs (T/24 + tik) ; k = 0, 1, 2, 3, 4, 5 O B. 1 cjs (Tt/24 + Ttk/2) ; k = 0, 1, 2, 3, 4, 5 O C. 1 cjs (T/24 + Ttk/4) ; k = 0, 1, 2, 3, 4, 5 O D. 1 cjs (T/24 + Tik/3) ; k = 0, 1, 2, 3, 4, 5
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