3. Under everyday conditions, air drag is proportional to v². Specifically, Fa = Dv² (where D is a constant that depends on air density, the cross-sectional area, and the object's shape). Thus, the faster an object is going the greater the air drag. When an object is falling straight down, there is a speed at which the net force on the object will be zero. This speed is known as TERMINAL VELOCITY. Apply the formula you derived for Fnet to the situation where an object has reached terminal velocity (Fnet = 0) to solve for D. Let v = v7 (terminal velocity) and express your answer in terms of m, g, & vr. D= 0.03028

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Chapter1: Units, Trigonometry. And Vectors
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Hello, I have a question about how to calculate for D. I keep getting decimals I dont understand it.

2. Come up with an expression for the net force for the situation described above (ball released from rest). Enter the expression in terms of the forces by
using the symbols listed above. Let down be positive.
F
Fnet =
G
3. Under everyday conditions, air drag is proportional to v?. Specifically, F = Dv2 (where D is a constant that depends on air density, the cross-sectional
area, and the object's shape). Thus, the faster an object is going the greater the air drag. When an object is falling straight down, there is a speed at
which the net force on the object will be zero. This speed is known as TERMINAL VELOCITY. Apply the formula you derived for Fnet to the situation
where an object has reached terminal velocity (Fnet = 0) to solve for D. Let v = vT (terminal velocity) and express your answer in terms of m, g, & vT.
D = 0.03028
Transcribed Image Text:2. Come up with an expression for the net force for the situation described above (ball released from rest). Enter the expression in terms of the forces by using the symbols listed above. Let down be positive. F Fnet = G 3. Under everyday conditions, air drag is proportional to v?. Specifically, F = Dv2 (where D is a constant that depends on air density, the cross-sectional area, and the object's shape). Thus, the faster an object is going the greater the air drag. When an object is falling straight down, there is a speed at which the net force on the object will be zero. This speed is known as TERMINAL VELOCITY. Apply the formula you derived for Fnet to the situation where an object has reached terminal velocity (Fnet = 0) to solve for D. Let v = vT (terminal velocity) and express your answer in terms of m, g, & vT. D = 0.03028
For this lab you will use the simulation below to investigate motion with and without air drag.
Initial Values
Height: 0 m
Angle: 90
Speed: 18 m/s
Time
1.83 s
Range
Om
Cannonball
Height
16.4 m
Mass
17.60 kg
31
Diameter
0.18 m
0.1
Gravity
9.81 m/s
M Air Resistance
Altitude
0m
Drag Coefficient: 0.47
0 m
90
15.0 m
Initial Speed 18 m/s
Normal
II O
Slow
Projectile Motion
PHET:
Intro
Vectors
Drag
Lab
Transcribed Image Text:For this lab you will use the simulation below to investigate motion with and without air drag. Initial Values Height: 0 m Angle: 90 Speed: 18 m/s Time 1.83 s Range Om Cannonball Height 16.4 m Mass 17.60 kg 31 Diameter 0.18 m 0.1 Gravity 9.81 m/s M Air Resistance Altitude 0m Drag Coefficient: 0.47 0 m 90 15.0 m Initial Speed 18 m/s Normal II O Slow Projectile Motion PHET: Intro Vectors Drag Lab
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