3. Two infinite sheets of equal and opposite charge are placed facing each other with a distance of 1.50 m separating them. The positive sheet is on the left and the negative sheet is on the right. If a lone point charge of -5.00 µC with a mass of 3.15 x 10- kg is at the midpoint between the plates and is released from rest, it reaches the positive sheet with a speed of 1200 m/s.
What is the total potential difference between the plates? What is the surface charge densities of the plate?if the point of charge had been released from at the position of the negative sheet from rest with what speed would it reach the positive sheet?
Using work-energy theorem
The sum of the change in kinetic energy of the particle and change in potential energy of the particle is zero.
Thus
Where m = mass of the particle, u = initial speed of the particle, v = final speed of the particle\
q = charge on particle, = Potential difference
The electric field in between two infinite sheets of equal and opposite charges is given by
Where Magnitude of surface charge density on plates
Permittivity of free space = 8.854 × 10- 12 C2m- 2N- 1
Step by step
Solved in 3 steps with 15 images